# Python | Consecutive chunks Product

• Last Updated : 29 Dec, 2019

Some of the classical problems in programming domain comes from different categories and one among them is finding the product of subsets. This particular problem is also common when we need to compute the product and store consecutive group product value. Let’s try different approaches to this problem in python language.

Method #1 : Using list comprehension + loop
The list comprehension can be used to perform the this particular task to filter out successive groups and product explicit function can be used to get the product of the filtered solution.

 `# Python3 code to demonstrate``# Consecutive chunks Product``# using list comprehension + loop`` ` `# getting Product``def` `prod(val) :``    ``res ``=` `1` `    ``for` `ele ``in` `val:``        ``res ``*``=` `ele``    ``return` `res `` ` `# initializing list``test_list ``=` `[``4``, ``7``, ``8``, ``10``, ``12``, ``15``, ``13``, ``17``, ``14``]`` ` `# printing original list ``print``(``"The original list : "` `+` `str``(test_list))`` ` `# using list comprehension + loop``# Consecutive chunks Product``res ``=` `[ prod(test_list[x : x ``+` `3``]) ``for` `x ``in` `range``(``0``, ``len``(test_list), ``3``)]`` ` `# printing result``print``(``"The chunked product list is : "` `+` `str``(res))`

Output :

```The original list : [4, 7, 8, 10, 12, 15, 13, 17, 14]
The chunked product list is : [224, 1800, 3094]
```

Method #2 : Using loop + itertools.islice()
The task of slicing the list into chunks is done by islice method here and the conventional task of getting the product is done by the explicit product function as the above method.

 `# Python3 code to demonstrate``# Consecutive chunks Product``# using itertools.islice() + loop``import` `itertools`` ` `# getting Product``def` `prod(val) :``    ``res ``=` `1` `    ``for` `ele ``in` `val:``        ``res ``*``=` `ele``    ``return` `res `` ` `# initializing list``test_list ``=` `[``4``, ``7``, ``8``, ``10``, ``12``, ``15``, ``13``, ``17``, ``14``]`` ` `# printing original list ``print``(``"The original list : "` `+` `str``(test_list))`` ` `# using itertools.islice() + loop``# Consecutive chunks Product``res ``=` `[prod(``list``(itertools.islice(test_list, i, i ``+` `3``))) ``for` `i ``in` `range``(``0``, ``len``(test_list), ``3``)]`` ` `# printing result``print``(``"The chunked product list is : "` `+` `str``(res))`

Output :

```The original list : [4, 7, 8, 10, 12, 15, 13, 17, 14]
The chunked product list is : [224, 1800, 3094]
```

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