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Break a list into chunks of size N in Python
• Difficulty Level : Medium
• Last Updated : 24 Apr, 2020

Method 1: Using yield
The yield keyword enables a function to comeback where it left off when it is called again. This is the critical difference from a regular function. A regular function cannot comes back where it left off. The yield keyword helps a function to remember its state. The yield enables a function to suspend and resume while it turns in a value at the time of the suspension of the execution.

 `my_list ``=` `[``'geeks'``, ``'for'``, ``'geeks'``, ``'like'``,``           ``'geeky'``,``'nerdy'``, ``'geek'``, ``'love'``,``               ``'questions'``,``'words'``, ``'life'``]`` ` `# Yield successive n-sized``# chunks from l.``def` `divide_chunks(l, n):``     ` `    ``# looping till length l``    ``for` `i ``in` `range``(``0``, ``len``(l), n): ``        ``yield` `l[i:i ``+` `n]`` ` `# How many elements each``# list should have``n ``=` `5`` ` `x ``=` `list``(divide_chunks(my_list, n))``print` `(x)`

Output:

```[['geeks', 'for', 'geeks', 'like', 'geeky'],
['nerdy', 'geek', 'love', 'questions', 'words'],
['life']]
```

Method 2: Using List comprehension
List comprehension is an elegant way to break a list in one line of code.

 `my_list ``=` `[``1``, ``2``, ``3``, ``4``, ``5``,``              ``6``, ``7``, ``8``, ``9``]`` ` `# How many elements each``# list should have``n ``=` `4` ` ` `# using list comprehension``final ``=` `[my_list[i ``*` `n:(i ``+` `1``) ``*` `n] ``for` `i ``in` `range``((``len``(my_list) ``+` `n ``-` `1``) ``/``/` `n )] ``print` `(final)`

Output:

```[[1, 2, 3, 4], [5, 6, 7, 8], ]
```

Alternate Implementation :

 `l ``=` `[``1``, ``2``, ``3``, ``4``, ``5``, ``6``, ``7``, ``8``, ``9``] ``  ` `# How many elements each ``# list should have ``n ``=` `4``  ` `# using list comprehension ``x ``=` `[l[i:i ``+` `n] ``for` `i ``in` `range``(``0``, ``len``(l), n)] ``print``(x)`

Output:

```[[1, 2, 3, 4], [5, 6, 7, 8], ]
```

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