# Python – Concatenate Kth element in Tuple List

• Last Updated : 19 Feb, 2020

While working with tuples, we store different data as different tuple elements. Sometimes, there is a need to print a specific information from the tuple. For instance, a piece of code would want just names to be printed of all the student data in concatenated format. Lets discuss certain ways how one can achieve solutions to this problem.

Method #1 : Using list comprehension + join()
List comprehension is the simplest way in which this problem can be solved. We can just iterate over only the specific index value in all the index and store it in a list and concat it after that using join().

 `# Python3 code to demonstrate ``# Concatenating Kth element in Tuple List``# using list comprehension `` ` `# initializing list of tuples``test_list ``=` `[(``1``, ``'Rash'``, ``21``), (``2``, ``'Varsha'``, ``20``), (``3``, ``'Kil'``, ``19``)]`` ` `# printing original list ``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `1`` ` `# using list comprehension + join() to concatenate names``res ``=` `" "``.join([lis[K] ``for` `lis ``in` `test_list])``     ` `# printing result``print` `(``"String with only Kth tuple element (i.e names) concatenated : "` `+` `str``(res))`
Output :
```The original list is : [(1, 'Rash', 21), (2, 'Varsha', 20), (3, 'Kil', 19)]
String with only Kth tuple element (i.e names) concatenated : Rash Varsha Kil
```

Method #2 : Using `map() + itemgetter() + join()`
map() coupled with itemgetter() can perform this task in more simpler way. map() maps all the element we access using itemgetter() and returns the result. The task of concatenation is performed using join().

 `# Python3 code to demonstrate ``# Concatenating Kth element in Tuple List``# using map() + itergetter() + join()``from` `operator ``import` `itemgetter`` ` `# initializing list of tuples``test_list ``=` `[(``1``, ``'Rash'``, ``21``), (``2``, ``'Varsha'``, ``20``), (``3``, ``'Kil'``, ``19``)]`` ` `# printing original list ``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `1` ` ` `# using map() + itergetter() + join() to get names``res ``=` `" "``.join(``list``(``map``(itemgetter(K), test_list)))``     ` `# printing result``print` `(``"String with only nth tuple element (i.e names) concatenated : "` `+` `str``(res))`
Output :
```The original list is : [(1, 'Rash', 21), (2, 'Varsha', 20), (3, 'Kil', 19)]
String with only Kth tuple element (i.e names) concatenated : Rash Varsha Kil
```

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