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Python – Concatenate Tuple to Dictionary Key
• Last Updated : 02 Sep, 2020

Given Tuples, convert them to dictionary with key being concatenated string.

Input : test_list = [((“gfg”, “is”, “best”), 10), ((“gfg”, “for”, “cs”), 15)]
Output : {‘gfg is best’: 10, ‘gfg for cs’: 15}
Explanation : Tuple strings concatenated as strings.

Input : test_list = [((“gfg”, “is”, “best”), 10)]
Output : {‘gfg is best’: 10}
Explanation : Tuple strings concatenated as strings.

Method #1 : Using loop + join()

In this, we perform the task of concatenation for dictionary key using join() and loop is used to render the required dictionary.

## Python3

 `# Python3 code to demonstrate working of ``# Concatenate Tuple to Dictionary Key``# Using loop + join()`` ` `# initializing list``test_list ``=` `[((``"gfg"``, ``"is"``, ``"best"``), ``10``), ((``"gfg"``, ``"good"``), ``1``), ((``"gfg"``, ``"for"``, ``"cs"``), ``15``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `res ``=` `{}``for` `sub ``in` `test_list:``     ` `  ``# joining for making key``  ``res[``" "``.join(sub[``0``])] ``=` `sub[``1``]`` ` `# printing result ``print``(``"The computed Dictionary : "` `+` `str``(res))`
Output
```The original list is : [(('gfg', 'is', 'best'), 10), (('gfg', 'good'), 1), (('gfg', 'for', 'cs'), 15)]
The computed Dictionary : {'gfg is best': 10, 'gfg good': 1, 'gfg for cs': 15}
```

Method #2 : Using dictionary comprehension

This is shorthand to above method, similar functionality, just one-liner on paper for compact solution.

## Python3

 `# Python3 code to demonstrate working of ``# Concatenate Tuple to Dictionary Key``# Using dictionary comprehension`` ` `# initializing list``test_list ``=` `[((``"gfg"``, ``"is"``, ``"best"``), ``10``), ((``"gfg"``, ``"good"``), ``1``), ((``"gfg"``, ``"for"``, ``"cs"``), ``15``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# one liner to solve problem ``res ``=` `{``' '``.join(key): val ``for` `key, val ``in` `test_list}`` ` `# printing result ``print``(``"The computed Dictionary : "` `+` `str``(res))`
Output
```The original list is : [(('gfg', 'is', 'best'), 10), (('gfg', 'good'), 1), (('gfg', 'for', 'cs'), 15)]
The computed Dictionary : {'gfg is best': 10, 'gfg good': 1, 'gfg for cs': 15}
```

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