Given K and a binary number, check if there exists k consecutive 1’s in the binary number.
Input : binary number = 101010101111 k = 4 Output : yes Explanation: at the last 4 index there exists 4 consecutive 1's Input : binary number = 11100000 k=5 Output : no Explanation: There is a maximum of 3 consecutive 1's in the given binary.
Approach: Create a new string with k 1’s. Using if condition check if there is new in s. In python if new in s: checks if there is any existence if new in s, hence returns true if there is else it returns a false.
Below is the Python implementation of the above approach:
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