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# Python – Check if a list is empty or not

• Difficulty Level : Easy
• Last Updated : 20 Mar, 2023

In this article, we will learn How to check if the given list is empty or not.

Example:

```Input: ['Geeks', 'Geeks', 'Geeks', 'Geeks', ]
Output: Yes Not Empty
Input: [ ]
Output: Empty```

## How to check if a list is empty in Python

### Method 1: Check the empty list using the len() With Comparison Operator

Let’s see how we can check whether a list is empty or not, in a less pythonic way. We should avoid this way of explicitly checking for a sequence or list

## Python3

 `# Python code to check for empty list``# Explicit way` `def` `Enquiry(lis1):``    ``if` `len``(lis1) ``=``=` `0``:``        ``return` `0``    ``else``:``        ``return` `1` `# Driver Code``lis1 ``=` `[]``if` `Enquiry(lis1):``    ``print``(``"The list is not empty"``)``else``:``    ``print``(``"Empty List"``)`

Output:

`Empty List`

Time complexity: O(n)

Auxiliary space: O(n), where n is length of list

### Method 2: Check the empty list using the implicit booleans

Now let’s see a more pythonic way to check for an empty list. This method of a check is an implicit way of checking and more preferable than the previous one.

## Python3

 `# Python code to check for empty list``# IMPLICIT way or Pythonic way``def` `Enquiry(lis1):``    ``if` `not` `lis1:``        ``return` `1``    ``else``:``        ``return` `0` `# Driver Code``lis1 ``=` `[]``if` `Enquiry(lis1):``    ``print``(``"The list is Empty"``)``else``:``    ``print``(``"The list is not empty"``)`

Output:

`The list is Empty`

### Method 4: Check the empty list using the PEP 8 recommended method

This is another method that allows us to determine whether a list in Python is empty. The most Pythonic method of checking the same is shown below.

## Python3

 `list1 ``=` `{``"a"``: ``1``, ``"b"``: ``2``, ``"c"``: ``3``}``list2 ``=` `[]` `if` `list2:``    ``print``(``"list is not empty"``)``else``:``    ``print``(``"list is empty"``)`

Output:

`list is empty`

## Numpythonic way

### Example 1

The previous methods that we used in normal Python don’t work for the Numpythonic way. Other methods that work fine for lists or other standard containers fail for NumPy arrays. This way fails with NumPy arrays because Numpy tries to cast the array to an array of bools and if this tries to evaluate all of those bools at once for some kind of aggregate truth value, it fails so we get a ValueError.

## Python3

 `# Numpythonic way with the previous method``# Returns ValueError``import` `numpy` `def` `Enquiry(lis1):``    ``return``(numpy.array(lis1))` `# Driver Code``lis1 ``=` `[``0``, ``1``]``if` `Enquiry(lis1):``    ``print``(``"Not Empty"``)``else``:``    ``print``(``"Empty"``)`

Output:

`None`

Error:

```Traceback (most recent call last):
File "/home/2d237324bb5211d7216c521441a750e9.py", line 7, in
if Enquiry(lis1):
ValueError: The truth value of an array with more than
one element is ambiguous. Use a.any() or a.all()```

### Example 2

In this example, we will see that even if the list is Not Empty, the output will show Empty. If the list contains one 0, then the if statement will incorrectly result.

## Python3

 `# Numpythonic way with the previous method``# Returns wrong result``import` `numpy`  `def` `Enquiry(lis1):``    ``return``(numpy.array(lis1))`  `# Driver Code``lis1 ``=` `[``0``, ]``if` `Enquiry(lis1):``    ``print``(``"Not Empty"``)``else``:``    ``print``(``"Empty"``)`

Output:

`Empty`

## Making the Numpythonic way work

### Example 1

If we have a NumPy array then the correct method in all cases is to use if .size. This size checks the size of the arrays and returns True or False accordingly. Example:

## Python3

 `# Numpythonic way to check emptiness``# Use of size``import` `numpy` `def` `Enquiry(lis1):``    ``return``(numpy.array(lis1))`  `# Driver Code``lis1 ``=` `[]``if` `Enquiry(lis1).size:``    ``print``(``"Not Empty"``)``else``:``    ``print``(``"Empty"``)`

Output:

`Empty`

### Example 2

This example shows the other case with a single 0 element, which failed in the previous cases.

## Python3

 `# Numpythonic way to check emptiness``# Use of size``import` `numpy` `def` `Enquiry(lis1):``    ``return``(numpy.array(lis1))` `# Driver Code``lis1 ``=` `[``0``, ]``if` `Enquiry(lis1).size:``    ``print``(``"Not Empty"``)``else``:``    ``print``(``"Empty"``)`

Output:

`Not Empty`

## Python3

 `# Python code to check for empty list``lis1 ``=` `[]``if` `lis1!``=``[]:``    ``print``(``"The list is not empty"``)``else``:``    ``print``(``"Empty List"``)`

Output

`Empty List`

## Python3

 `lst``=` `[``'Geeks'``, ``'Geeks'``, ``'Geeks'``, ``'Geeks'``, ]``x``=``[``"not empty"` `if` `len``(lst)>``0` `else` `"empty"``]``print``(x)`

Output

`['not empty']`

#### Using the any() function:

The any() function returns True if any element in an iterable is True, and False otherwise. This can be used to check if a list is empty or not by passing the list to any() as an argument.

Here is an example of how to use any() to check if a list is empty:

## Python3

 `def` `is_empty(lst):``    ``return` `not` `any``(lst)` `lst1 ``=` `[``1``, ``2``, ``3``]``lst2 ``=` `[]` `print``(is_empty(lst1))  ``# Output: False``print``(is_empty(lst2))  ``# Output: True`

Output

```False
True```

Method : Comparing given list with empty list using == operator

## Python3

 `# Python code to check for empty list``lis1 ``=` `[]``if` `lis1``=``=``[]:``    ``print``(``"Empty List"``)``else``:``    ``print``(``"The list is not empty"``)`

Output

`Empty List`

This approach has the advantage of being concise and easy to understand. It is also generally faster than other approaches that involve looping through the elements of the list.

My Personal Notes arrow_drop_up