Program to print N minimum elements from list of integers

Given a list of integers, the task is to generate another list with N minimum elements.

Examples:

Input: {23, 1, 6, 2, 90}
Output: {1, 2}

Input: {34, 21, 56, 42, 89, 90, -1}
Output: {-1, 21}

Approach: The idea is to use the concept used in Find the smallest and second smallest elements in an array.

First, find the smallest number in the given list.
Then add that current minimum element to another list that will contain the N minimum elements.
Remove the current minimum element from the given list.
Continue with the same process until the N minimum elements are found.

Below is the implementation of the above approach:

C++

// C++ program to find N  
// minimum elements 
#include <bits/stdc++.h> 
using namespace std; 
  
void Nminelements(vector<int>list1, int N) 
{ 
    vector<int> final_list; 
    int n = list1.size(); 
    for (int i = 0; i < N; i++)  
    { 
        int min1 = 9999999; 
        for (int j = 0; j < n; j++) 
        { 
            if (list1[j] < min1) 
                min1 = list1[j]; 
        } 
          
        // remove minimum element  
        // from list so that it do 
        // not come in calculation again          
        list1.erase(remove(list1.begin(),  
                           list1.end(), min1),  
                           list1.end()); 
        final_list.push_back(min1); 
    } 
    for(int i = 0; i < final_list.size(); i++) 
    cout << final_list[i] << " "; 
}  
  
// Driver code 
int main() 
{ 
    vector<int> list1 = {4, 78, 34, 10,  
                         8, 21, 11, 231}; 
    int N = 2; 
    Nminelements(list1, N); 
} 
  
// This code is contributed by Subhadeep 

Python3

# Python program to find N minimum elements 
def Nminelements(list1, N): 
    final_list =[]; 
   
    for i in range(0, N):     
        min1 = 9999999; 
           
        for j in range(len(list1)):       
            if list1[j]<min1: 
                min1 = list1[j]; 
  
        # remove minimum element from list so  
        # that it do not come in calculation again          
        list1.remove(min1); 
        final_list.append(min1) 
           
    print(final_list) 
   
# Driver code 
list1 = [4, 78, 34, 10, 8, 21, 11, 231]; 
N = 2; 
Nminelements(list1, N) 

Output:

4 8

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