# Program to make Indian Flag in Python | Step by Step

Last Updated : 04 Apr, 2024

Here, We’ll be making Indian Flag in Python using Spyder tool which is a part of Anaconda interface. It is the beginner’s practice problem for python programmers.

Prerequisite:

The only prerequisite for this code is little knowledge of basic python programming. You may install anaconda from here if you don’t have any interpreter for python.

Approach:

We will be using simple characteristic equations of lines and circles in this code. It is recommended to try on your own before getting to the solution altogether.

Import these 3 packages for the functions used in this code.

`import skimage               # for using image processing functionsimport osfrom skimage import io       # for using imshow function`

1. Read an image of at least the expected dimensions of the flag.

`image2 = io.imread('C:\Users\geeksforgeeks\Desktop\index.jpg')`

2. Let us assume the dimensions of the flag to be 189px high and 267px wide.

`x = 189/2y = 267/2r = 189/6`

3. Start two for loops to iterate to every pixel of the image.

`for i in range(0, 189):    for j in range(0, 267):`

Inside the inner loop perform 3-(a) and 3-(b). 3-(a). By dividing the image into 3 equal part height-wise color the image in orange, white and green.

`if i in range(0, 189/3):            image2[i][j] = [255, 128, 64]       # Color coding for Orange         elif i in range(189/3, 189*2/3):            image2[i][j] = [255, 255, 255]      # Color coding for White        else:            image2[i][j] = [0, 128, 0]          # Color coding for Green`

io.imshow(image2)

3-(b). Now it’s time to draw the circle at the center for the Ashoka Chakra, using equation of circle.

`if (( pow((x-i), 2) + pow((y-j), 2) ) = pow(r-2, 2)):            image2[i][j] = [0, 0, 255]`

io.imshow(image2)

4. To draw spokes of the Chakra, we need to use equation of lines which stays inside the circle only, here I have drawn 4 x 2 spokes, however all 24 spokes can be drawn by using 12 equations as each line leads to two opposite spokes.

`for i in range(189/3, 189*2/3):    for j in range(267/3, 267*2/3):        if ((i == 189/2) or (j == 267/2) or (i+39 == j or                (i+39+j == 266))) and (( pow((x-i), 2) +                        pow((y-j), 2) ) <= pow(r, 2)) :            image2[i][j] = [0, 0, 255]`

5. It’s time to view our image now so we will use <mshow function.

`io.imshow(image2)`

And Over Indian Flag in just 5 steps. The overall code will look something like this…

Python3 1== ```&quot;&quot;&quot; @author: geeksforgeeks &quot;&quot;&quot; # Packages import skimage import os from skimage import io # Reading image file image2 = io.imread('C:\Users\KRISHNA\Desktop\index.jpg') # Setting dimensions boundaries x = 189 / 2 y = 267 / 2 r = 189 / 6 # Iterating to all the pixels in the set boundaries for i in range(0, 189): for j in range(0, 267): if i in range(0, 189 / 3): image2[i][j] = [255, 128, 64] # Orange Color elif i in range(189 / 3, 189 * 2 / 3): image2[i][j] = [255, 255, 255] # White Color else: image2[i][j] = [0, 128, 0] # Green Color # Equation for 2px thick ring if (( pow((x-i), 2) + pow((y-j), 2) ) &lt;= pow(r + 1, 2)) and(( pow((x-i), 2) + pow((y-j), 2) ) &gt;= pow(r-2, 2)): image2[i][j] = [0, 0, 255] # Blue Color # Iterating within the ring for i in range(189 / 3, 189 * 2 / 3): for j in range(267 / 3, 267 * 2 / 3): # Equation to draw 4 straight lines if ((i == 189 / 2) or (j == 267 / 2) or (i + 39 == j or (i + 39 + j == 266))) and (( pow((x-i), 2) + pow((y-j), 2) ) &lt;= pow(r, 2)) : image2[i][j] = [0, 0, 255] # Blue Color io.imshow(image2) # Output ```

Output:

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