A certain number of men can do a certain piece of work in D days. If there were m more men engaged in the work then the work can be done in d days less. The task is to find how many men were there initially.
Input: D = 5, m = 4, d = 4
Input: D = 180, m = 30, d = 20
Approach: Let the initial number of men be M and days be D
Amount of work completed M men in D days will be M * D
i.e. Work Done = M * D …(1)
If there are M + m men then the same amount of work is completed in D – d days.
i.e. Work Done = (M + m) * (D – d) …(2)
Equating equations 1 and 2,
M * D = (M + m) * (D – d)
M * D = M * (D – d) + m * (D – d)
M * D – M * (D – d) = m * (D – d)
M * (D – (D – d)) = m * (D – d)
M = m * (D – d) / d
Below is the implementation of the above approach:
- Program to find the number from given holes
- Program to find the Nth number of the series 2, 10, 24, 44, 70.....
- Program to find Nth odd Fibonacci Number
- Program to find the Nth Harmonic Number
- Program to find Star number
- Program to find the Nth Prime Number
- C++ Program to find sum of even factors of a number
- C program to find Decagonal Number
- Program to find Cullen Number
- Program to find the next prime number
- Program to find the Hidden Number
- Program to find the nth Kynea number
- Program to find number of squares in a chessboard
- Program to find last two digits of Nth Fibonacci number
- Program to find last digit of n'th Fibonnaci Number
If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to email@example.com. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.