# Program to find compound interest

What is ‘Compound interest’ ?
Compound interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on interest. It is the result of reinvesting interest, rather than paying it out, so that interest in the next period is then earned on the principal sum plus previously-accumulated interest. Compound interest is standard in finance and economics.
Compound interest may be contrasted with simple interest, where interest is not added to the principal, so there is no compounding.
Compound Interest formula:

Formula: to calculate compound interest annually is given by:
Amount= P(1 + R/100)t

Compound Interest = Amount – P
Where,
P is the principal amount
R is the rate and
T is the time span

Pseudo Code:

Input principal amount. Store it in some variable say principal
Input time in some variable say time.
Input rate in some variable say rate.
Calculate Amount using the formula,
Amount = principal* (1 + rate / 100)  time).
Calculate Compound Interest using Formula.
Finally, print the resultant value of CI.

Example:

Input: Principal (amount): 1200, Time: 2, Rate: 5.4
Output: Compound Interest = 133.099243

## C++

 `// CPP program to find compound interest for ` `// given values. ` `#include ` `using` `namespace` `std; ` ` `  `int` `main() ` `{ ` `    ``double` `principal = 10000, rate = 5, ``time` `= 2; ` ` `  `    ``/* Calculate compound interest */` `    ``double` `A = principal * (``pow``((1 + rate / 100), ``time``)); ` `      ``double` `CI = A- principal; ` ` `  `    ``cout << ``"Compound interest is "` `<< CI; ` ` `  `    ``return` `0; ` `} ` `//This Code is Contributed by Sahil Rai.`

## C

 `// C program to calculate Compound Interest ` `#include ` `#include // for using pow function we must include math.h ` ` `  `int` `main() { ` `  ``double` `principal = 10000; ``// principal amount ` `  ``double` `rate = 5; ``//annual rate of interest ` `  ``double` `time` `= 2; ``// time ` ` `  `  ``// Calculating compound Interest ` `    ``double` `Amount = principal * (``pow``((1 + rate / 100), ``time``)); ` `    ``double` `CI = Amount - principal; ` `  `  `    ``printf``(``"Compound Interest is : %lf"``,CI); ` `    ``return` `0; ` `} `

## Java

 `// Java program to find compound interest for ` `// given values. ` `import` `java.io.*; ` ` `  `class` `GFG ` `{ ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``double` `principal = ``10000``, rate = ``5``, time = ``2``; ` ` `  `        ``/* Calculate compound interest */` `        ``double` `A = principal * ` `                    ``(Math.pow((``1` `+ rate / ``100``), time)); ` `          ``double` `CI = A - principle; ` `         `  `        ``System.out.println(``"Compound Interest is "``+ CI); ` `    ``} ` `} ` ` `  `//This Code is Contributed by Sahil Rai.`

## Python3

 `# Python3 program to find compound ` `# interest for given values. ` ` `  `def` `compound_interest(principal, rate, time): ` ` `  `    ``# Calculates compound interest  ` `    ``A ``=` `principal ``*` `(``pow``((``1` `+` `rate ``/` `100``), time)) ` `    ``CI``=` `A ``-` `principal ` `    ``print``(``"Compound interest is"``, CI) ` ` `  ` `  `compound_interest(``10000``, ``5``, ``2``) ` ` `  `#This Code is Contributed by Sahil Rai.`

## C#

 `// C# program to find compound  ` `// interest for given values ` `using` `System; ` ` `  `class` `GFG { ` ` `  `    ``// Driver Code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``double` `principal = 10000, rate = 5, time = 2; ` ` `  `        ``// Calculate compound interest  ` `        ``double` `A = principal * (Math.Pow((1 + ` `                    ``rate / 100), time)); ` `          ``double` `CI = A - principal; ` `         `  `        ``Console.Write(``"Compound Interest is "``+ CI); ` `    ``} ` `} ` ` `  `//This Code is Contributed by Sahil Rai. `

## PHP

 ` `

## Javascript

 ` ` ` `  `// This Code is Contributed by Sahil Rai.`

Output:

`Compound interest is 1025`

Time complexity: O(1), as there is no loop used so constant time
Auxiliary Space: O(1)

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