Given that a certain amount of money becomes T1 times itself in N1 years. The task is to find the number of years i.e. N2 so that the amount becomes T2 times itself at the same rate of simple interest.
Input: T1 = 5, N1 = 7, T2 = 25
Input: T1 = 3, N1 = 5, T2 = 6
Let us consider the 1st Example where T1 = 5, N1 = 7, T2 = 25
Now, Let P principal becomes 5P i.e (T1 * P) then Simple interest received is 4P.
(As S.I = Amount – P)
Now, in the second case, P has become 25P i.e (T2 * P) then simple interest received is 24P.
Now if we received 4P interest in N1 i.e 7 years then we will get an interest of 24P
in 7 * 6 years i.e in 42 years.
Below is the implementation of the above approach:
- Simple Interest
- Program to find simple interest
- Difference between two given times
- Probability of getting a sum on throwing 2 Dices N times
- Find the value of XXXX.....(N times) % M where N is large
- How to print N times without using loops or recursion ?
- GCD of two numbers formed by n repeating x and y times
- First element that appears even number of times in an array
- Convert a number of length N such that it contains any one digit at least 'K' times
- Count different numbers possible using all the digits their frequency times
- Find Nth smallest number that is divisible by 100 exactly K times
- Count of Numbers in a Range where digit d occurs exactly K times
- Element which occurs consecutively in a given subarray more than or equal to K times
- Maximum number of dots after throwing a dice N times
- Maximum profit by buying and selling a share at most k times
If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to firstname.lastname@example.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.