Given two numbers N and M. The task is to find the product of the 2 numbers using recursion.
Note: The numbers can be both positive or negative.
Input : N = 5 , M = 3 Output : 15 Input : N = 5 , M = -3 Output : -15 Input : N = -5 , M = 3 Output : -15 Input : N = -5 , M = -3 Output:15
A recursive solution to the above problem for only positive numbers is already discussed in the previous article. In this post, a recursive solution for finding the product for both positive and negative numbers is discussed.
Below is the step by step approach:
- Check if one or both of the numbers are negative.
- If the number passed in the second parameter is negative swap the parameters and call the function again.
- If both of the parameters are negative call the function again and pass the absolute values of the numbers as parameters.
- If n>m call the function with swapped parameters for less execution time of the function.
- As long as m is not 0 keep on calling the function with subcase n, m-1 and return n + multrecur(n, m-1).
Below is the implementation of the above approach:
5 * 3 = 15 5 * (-3) = -15 (-5) * 3 = -15 (-5) * (-3) = 15
- Product of 2 Numbers using Recursion
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- Program for dot product and cross product of two vectors
- Sum of the series 1^1 + 2^2 + 3^3 + ..... + n^n using recursion
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- Practice Questions for Recursion | Set 7
- Print 1 to 100 in C++, without loop and recursion
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