Given two strings, print all the common characters in lexicographical order. If there are no common letters, print -1. All letters are lower case.
Input : string1 : geeks string2 : forgeeks Output : eegks Explanation: The letters that are common between the two strings are e(2 times), k(1 time) and s(1 time). Hence the lexicographical output is "eegks" Input : string1 : hhhhhello string2 : gfghhmh Output : hhh
The idea is to use character count arrays.
1) Count occurrences of all characters from ‘a’ to ‘z’ in first and second strings. Store these counts in two arrays a1 and a2.
2) Traverse a1 and a2 (Note size of both is 26). For every index i, print character ‘a’ + i number of times equal min(a1[i], a2[i]).
Below is implementation of above steps.
Time Complexity: If we consider n = length(larger string), then this algorithm runs in O(n) complexity.
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