Placement new operator in C++

Placement new is a variation new operator in C++. Normal new operator does two things : (1) Allocates memory (2) Constructs an object in allocated memory.

Placement new allows us to separate above two things. In placement new, we can pass a preallocated memory and construct an object in the passed memory.

new vs placement new

  • Normal new allocates memory in heap and constructs objects tehre whereas using placement new, object construction can be done at known address.
  • With normal new, it is not known that, at what address or memory location it’s pointing to, whereas the address or memory location that it’s pointing is known while using placement new.
  • The deallocation is done using delete operation when allocation is done by new but there is no placement delete, but if it is needed one can write it with the help of destructor


new (address) (type) initializer
As we can see, we can specify an address
where we want a new object of given type 
to be constructed.

When to prefer using placement new ?

As it allows to construct an object on memory that is already allocated , it is required for optimizations as it is faster not to re-allocate all the time. There may be cases when it is required to re-construct an object multiple times so, placement new operator might be more efficient in these cases.

// C++ program to illustrate the placement new operator
using namespace std;

int main()
    // buffer on stack
    unsigned char buf[sizeof(int)*2] ;

    // placement new in buf
    int *pInt = new (buf) int(3);

    int *qInt = new (buf + sizeof (int)) int(5);
    int *pBuf = (int*)(buf+0) ;
    int *qBuf = (int*) (buf + sizeof(int));
    cout << "Buff Addr             Int Addr" << endl;
    cout << pBuf <<"             " << pInt << endl;
    cout << qBuf <<"             " << qInt << endl;
    cout << "------------------------------" << endl;
    cout << "1st Int             2nd Int" << endl;
    cout << *pBuf << "                         "
         << *qBuf << endl;

    return 0;


Buff Addr              Int Addr
0x69fed8               0x69fed8
0x69fedc               0x69fedc
1st Int                2nd Int
3                      5

The diagram below pictorially shows what is actually happening in above C++ program.

Below is a another simple implementation in C++ to illustrate the use of placement new in C++ :

// C++ program to illustrate the placement new operator
using namespace std;
int main()
    // initial value of X
    int X = 10;

    cout << "Before placement new :" << endl;
    cout << "X : " << X << endl;
    cout << "&X : " << &X << endl;

    // Placement new changes the value of X to 100
    int *mem = new (&X) int(100);

    cout << "\nAfter placement new :" << endl;
    cout << "X : " << X << endl;
    cout << "mem : " << mem << endl;
    cout << "&X : " << &X << endl;

    return 0;


Before placement new :
X : 10
&X : 0x69fee8

After placement new :
X : 100
mem : 0x69fee8
&X : 0x69fee8

Explanation: Here, it is clear that a new value of x is assigned at the address of x with the help of placement new operator. This is clear by the fact that the value of &X and mem is equal.
The diagram below pictorially shows what is actually happening in above C++ program.

How to delete the memory allocated by placement new ?

The operator delete can only delete the storage created in heap, so when placement new is used delete operator cannot be used to delete the storage. In the case of memory allocation using placement new operator , since it is created in stack the compiler knows when to delete it and it will handle deallocation of the memory automatically. If required, one can write it with the help of destructor as shown below.

// C++ program to illustrate using destructor for
// deleting memory allocated by placement new
using namespace std;

class Complex
    double re_, im_;
    // Constructor
    Complex(double re = 0, double im = 0): re_(re), im_(im)
        cout << "Constructor : (" << re_
             << ", " << im_ << ")" << endl;

    // Destructor
        cout << "Destructor : (" << re_ << ", "
             << im_ << ")" << endl;

    double normal()
        return sqrt(re_*re_ + im_*im_);

    void print()
        cout << "|" << re_ <<" +j" << im_
             << " | = " << normal() << endl;

// Driver code
int main()
    // buffer on stack
    unsigned char buf[100];

    Complex* pc = new Complex(4.2, 5.3);
    Complex* pd = new Complex[2];

    // using placement new
    Complex *pe = new (buf) Complex(2.6, 3.9);

    // use objects
    pc -> print();

    // Release objects
    // calls destructor and then release memory
    delete pc;

    // Calls the destructor for object pd[0]
    // and then release memory
    // and it does same for pd[1]
    delete [] pd;

    // No delete : Explicit call to Destructor.

    return 0;


Constructor : (4.2, 5.3)
Constructor : (0, 0)
Constructor : (0, 0)
Constructor : (2.6, 3.9)
|4.2 +j5.3 | = 6.7624
|0 +j0 | = 0
|0 +j0 | = 0
|2.6 +j3.9 | = 4.68722
Destructor : (4.2, 5.3)
Destructor : (0, 0)
Destructor : (0, 0)
Destructor : (2.6, 3.9)

Explanation: Here the destructor is explicitly called because here it cannot be packaged within the delete operator because delete will need to release the memory which you do not have here and it cannot be implicit as it is a dynamic process which we want to mange yourself.

When will placement new operator show segmentation fault ?

The placement new operator should be used with care. The address which is passed can be a reference or a pointer  pointing to a valid memory location. It may show error when the address passed is :

  • A pointer such as NULL pointer.
  • A pointer that is not pointing to any location.
  • It cannot be a void pointer unless it points to some location.
// C++ program to illustrate segmentation fault
// while using placement new operator
using namespace std;

int main()
    // Fine
    int i = 10;
    int *ipt = &i ;
    int *i1 = new(ipt) int(9) ;

    // Incorrect as ip may not
    // be a valid address
    int *ip;
    int *i2 = new(ip) int(4) ;

    // Fine
    void *vd = &i;
    int *i3 = new(vd) int(34) ;

    // Incorrect as x is not an address
    int x;
    int *i5 = new(x) int(3) ;

    return 0;
Segmentation fault

Advantages of placement new operator over new operator

  • The address of memory allocation is known before hand.
  • Useful when building a memory pool, a garbage collector or simply when performance and exception safety are paramount.
  • There’s no danger of allocation failure since the memory has already been allocated, and constructing an object on a pre-allocated buffer takes less time.
  • This feature becomes useful while working in an environment with limited resources.

This article is contributed by MAZHAR IMAM KHAN. If you like GeeksforGeeks and would like to contribute, you can also write an article using or mail your article to See your article appearing on the GeeksforGeeks main page and help other Geeks.

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