# Python | Extract Combination Mapping in two lists

Sometimes, while working with Python lists, we can have a problem in which we have two lists and require to find the all possible mappings possible in all combinations. This can have possible application in mathematical problems. Let’s discuss certain way in which this problem can be solved.

Method : Using `zip() + product()`
With these functions this problem can be solved and would require two steps to perform it. In the 1st step, we find all the combinations of elements using `product()` and as a part of 2nd step, we perform the possible pairing with the result of step 1 using `zip()` and output the desired result.

 `# Python3 code to demonstrate working of ` `# Extract Combination Mapping in two lists ` `# using zip() + product() ` `from` `itertools ``import` `product ` ` `  `# initialize lists ` `test_list1 ``=` `[``3``, ``4``, ``5``] ` `test_list2 ``=` `[``'x'``, ``'y'``] ` ` `  `# printing original lists ` `print``(``"The original list 1 is : "` `+` `str``(test_list1)) ` `print``(``"The original list 2 is : "` `+` `str``(test_list2)) ` ` `  `# Extract Combination Mapping in two lists ` `# using zip() + product() ` `res ``=` `list``(``list``(``zip``(test_list1, ele)) ``for` `ele ``in` `product(test_list2, repeat ``=` `len``(test_list1))) ` ` `  `# printing result ` `print``(``"Mapped Combination result : "` `+` `str``(res)) `

Output :

The original list 1 is : [3, 4, 5]
The original list 2 is : [‘x’, ‘y’]
Mapped Combination result : [[(3, ‘x’), (4, ‘x’), (5, ‘x’)], [(3, ‘x’), (4, ‘x’), (5, ‘y’)], [(3, ‘x’), (4, ‘y’), (5, ‘x’)], [(3, ‘x’), (4, ‘y’), (5, ‘y’)], [(3, ‘y’), (4, ‘x’), (5, ‘x’)], [(3, ‘y’), (4, ‘x’), (5, ‘y’)], [(3, ‘y’), (4, ‘y’), (5, ‘x’)], [(3, ‘y’), (4, ‘y’), (5, ‘y’)]]

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