Perfect Number Program in Python

In this article, we will see how we can check if a number is a perfect number or not in Python.

Perfect Number Program in Python

Below are some of the ways by which we can check if the number is a perfect number or not in Python:

Using for Loop

In this approach, we simply take a number from the user and make a variable named Sum initially its value is 0 and then we make a logic by using the for loop along with the conditional statement of if/ else. Finally, we get proper output.

Python3

# Perfect Number by using For_loop
Input_Number = 78
Sum = 0
for i in range(1, Input_Number):
    if(Input_Number % i == 0):
        Sum = Sum + i
if (Sum == Input_Number):
    print("Number is a Perfect Number.")
else:
    print("Number is not a Perfect Number.")

Output

Number is not a Perfect Number.

Using List Comprehension

Here, in checkIsPerfectNumber(input_Number_is), we leverage the beauty of list comprehension to succinctly end up aware of divisors. The sum of those divisors is then in contrast to the authentic huge range to envision perfection.

Python3

def checkIsPerfectNumber(number):
    divisors = sum([i for i in range(1, number) if number % i == 0])
    return number == divisors

input_Number_is = 6

if checkIsPerfectNumber(input_Number_is):
    print("Number is a Perfect Number.")
else:
    print("Number is not a Perfect Number.")

Output

Number is a Perfect Number.

Using filter() method

In this technique, isPerfectNumberFilterMethod(number), The sum of those divisors is then in contrast to the specific amount to determine if it is exceptional.

Python3

def IsPerfectNumberFilterMethod(number):

    divisors = list(filter(lambda x: number % x == 0, range(1, number)))
    return sum(divisors) == number

input_Number_is = 25

if IsPerfectNumberFilterMethod(input_Number_is):
    print("Number is a Perfect Number.")
else:
    print("Number is not a Perfect Number.")

Output

Number is not a Perfect Number.