Skip to content
Related Articles

Related Articles

Improve Article

Output of python program | Set 12(Lists and Tuples)

  • Difficulty Level : Medium
  • Last Updated : 24 Aug, 2021
Geek Week

Prerequisite: List and Tuples 
Note: Output of all these programs is tested on Python3

1) What is the output of the following program? 

PYTHON




L1 = []
L1.append([1, [2, 3], 4])
L1.extend([7, 8, 9])
print(L1[0][1][1] + L1[2])

a) Type Error: can only concatenate list (not “int”) to list 
b) 12 
c) 11 
d) 38 

Ans: (c) 
Explanation: In the print(), indexing is used. L1[0] denotes [1, [2, 3], 4], L1[0][1] denotes [2, 3], 
L1[0][1][1] = 3 and L1[2] = 8. Thus, the two integers are added, 3 + 8 = 11 and output comes as 11.

2) What is the output of the following program? 

PYTHON




L1 = [1, 1.33, 'GFG', 0, 'NO', None, 'G', True]
val1, val2 = 0, ''
for x in L1:
    if(type(x) == int or type(x) == float):
        val1 += x
    elif(type(x) == str):
        val2 += x
    else:
        break
print(val1, val2)

a) 2 GFGNO 
b) 2.33 GFGNOG 
c) 2.33 GFGNONoneGTrue 
d) 2.33 GFGNO 



Ans: (d) 
Explanation: val1 will only have integer and floating values val1 = 1 + 1.33 + 0 = 2.33 and val2 will have string
             values val2 ='GFG' + 'NO' = 'GFGNO'. String 'G' will not be part of val2 as the for loop will break at None,
             thus 'G' will not be added to val2.

3) What is the output of the following program? 

Python3




L1 = [1, 2, 3, 4]
L2 = L1
L3 = L1.copy()
L4 = L3
L1[0] = [5]
print(L1, L2, L3, L4)

a) [5, 2, 3, 4] [5, 2, 3, 4] [1, 2, 3, 4] [1, 2, 3, 4] 
b) [[5], 2, 3, 4] [[5], 2, 3, 4] [[5], 2, 3, 4] [1, 2, 3, 4] 
c) [5, 2, 3, 4] [5, 2, 3, 4] [5, 2, 3, 4] [1, 2, 3, 4] 
d) [[5], 2, 3, 4] [[5], 2, 3, 4] [1, 2, 3, 4] [1, 2, 3, 4] 

Ans: (d) 
Explanation: L2 is the reference pointing to the same object as L1,
             while L3 and L4 are single recursive Copy(Shallow Copy) of List L1.
             L1[0] = [5], implies that at index 0, list [5] will be present and not integer value 5.

4) What is the output of the following program?  

PYTHON




import sys
L1 = tuple()
print(sys.getsizeof(L1), end = " ")
L1 = (1, 2)
print(sys.getsizeof(L1), end = " ")
L1 = (1, 3, (4, 5))
print(sys.getsizeof(L1), end = " ")
L1 = (1, 2, 3, 4, 5, [3, 4], 'p', '8', 9.777, (1, 3))
print(sys.getsizeof(L1))

a) 0 2 3 10 
b) 32 34 35 42 
c) 48 64 72 128 
d) 48 144 192 480 

Ans: (c) 
Explanation: An Empty Tuple has 48 Bytes as Overhead size and each additional element requires 8 Bytes. 
(1, 2) Size: 48 + 2 * 8 = 64 
(1, 3, (4, 5)) Size: 48 + 3 * 8 = 72 
(1, 2, 3, 4, 5, [3, 4], 'p', '8', 9.777, (1, 3)) Size: 48 + 10 * 8 = 128 

5) What is the output of the following program?  

PYTHON




T1 = (1)
T2 = (3, 4)
T1 += 5
print(T1)
print(T1 + T2)

a) TypeError 
b) (1, 5, 3, 4) 
c) 1 TypeError 
d) 6 TypeError 

Ans: (d) 
Explanation: T1 is an integer while T2 is tuple. Thus T1 will become 1 + 5 = 6. But an integer and tuple cannot be added, it will throw TypeError.

This article is contributed by Piyush Doorwar. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks. 
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
 




My Personal Notes arrow_drop_up
Recommended Articles
Page :