# Output of C++ Program | Set 11

• Difficulty Level : Medium
• Last Updated : 27 Dec, 2016

Predict the output of following C++ programs.

Question 1

 #includeusing namespace std;  class Point{private:    int x;    int y;public:    Point(const Point&p) { x = p.x; y = p.y; }    void setX(int i) {x = i;}    void setY(int j) {y = j;}    int getX() {return x;}    int getY() {return y;}    void print() { cout << "x = " << getX() << ", y = " << getY(); }};    int main(){    Point p1;    p1.setX(10);    p1.setY(20);    Point p2 = p1;    p2.print();    return 0;}

Output: Compiler Error in first line of main(), i.e., “Point p1;”

Since there is a user defined constructor, compiler doesn’t create the default constructor (See this GFact). If we remove the copy constructor from class Point, the program works fine and prints the output as “x = 10, y = 20”

Question 2

 #includeusing namespace std;  int main(){    int *ptr = new int(5);    cout << *ptr;    return 0;}

Output: 5
The new operator can also initialize primitive data types. In the above program, the value at address ‘ptr ‘ is initialized as 5 using the new operator.

Question 3

 #include using namespace std;  class Fraction{private:    int den;    int num;public:   void print() { cout << num << "/" << den; }   Fraction() { num = 1; den = 1; }   int &Den() { return den; }   int &Num() { return num; }};  int main(){   Fraction f1;   f1.Num() = 7;   f1.Den() = 9;   f1.print();   return 0;}

Output: 7/9
The methods Num() and Den() return references to num and den respectively. Since references are returned, the returned values can be uses as an lvalue, and the private members den and num are modified. The program compiles and runs fine, but this kind of class design is strongly discouraged (See this). Returning reference to private variable allows users of the class to change private data directly which defeats the purpose of encapsulation.

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