# Output of C++ programs | Set 50

Last Updated : 07 Jul, 2021

Predict the output of the following C++ programs:

• Question 1

## CPP

 `#include ` `using` `namespace` `std;` `int` `main()` `{` `    ``void` `a = 10, b = 10;` `    ``int` `c;` `    ``c = a + b;` `    ``cout << c;` `    ``return` `0;` `}`

• Output:

`1804289383`
• Explanation: As the declared number is an integer, It will produce the random number from 0 to RAND_MAX. The value of RAND_MAX is library-dependent but is guaranteed to be at least 32767 on any standard library implementation.
• Question 2:

## CPP

 `#include `   `using` `namespace` `std;`   `int` `array1[] = { 1200, 200, 2300, 1230, 1543 };` `int` `array2[] = { 12, 14, 16, 18, 20 };` `int` `temp, result = 0;` `int` `main()` `{` `    ``for` `(temp = 0; temp < 5; temp++) {` `        ``result += array1[temp];` `    ``}` `    ``for` `(temp = 0; temp < 5; temp++) {` `        ``result += array2[temp];` `    ``}` `    ``cout << result;` `    ``return` `0;` `}`

• Output:

`2147483647`
• Explanation: The output is Compiler Dependent. RAND_MAX is a function used by the compiler to create a maximum random number.
• Question 3:

## CPP

 `#include ` `using` `namespace` `std;` `int` `main()` `{` `    ``int` `a = 5, b = 10, c = 15;` `    ``int` `arr[3] = { &a, &b, &c };` `    ``cout << *arr[*arr[1] - 8];` `    ``return` `0;` `}`

• Output:

`Compile time error`
• Explanation: void will not accept any values to its type.

• Question 4:

## CPP

 `#include ` `using` `namespace` `std;` `int` `main()` `{` `    ``int` `array[] = { 10, 20, 30 };` `    ``cout << -2 [array];` `    ``return` `0;` `}`

• Output:

`6553`
• Explanation: In this program we are adding the every element of two arrays. All the elements of array1[] and array2[] will be added and the sum will be stored in result and hence output is 6553.
• Question 5:

## CPP

 `#include ` `using` `namespace` `std;` `int` `main()` `{` `    ``int` `const` `p = 5;` `    ``cout << ++p;` `    ``return` `0;` `}`

• Output:

`Compile time error!`
• Explanation: The conversion is invalid in this array. The array arr[] is declared to hold integer type value but we are trying to assign references(addresses) to the array so it will arise error. The following compilation error will be raised:

`cannot convert from â€˜int *â€™ to â€˜intâ€™`
• Question 6:

## CPP

 `#include ` `using` `namespace` `std;` `int` `main()` `{` `    ``char` `arr[20];` `    ``int` `i;` `    ``for` `(i = 0; i < 10; i++)` `        ``*(arr + i) = 65 + i;` `    ``*(arr + i) = ``'\0'``;` `    ``cout << arr;` `    ``return` `(0);` `}`

• Output:

`-30`
• Explanation: -2[array]: this statement is equivalent to -(array[2]). At the zero index 30 is stored hence negation of 30 will be printed due to unary operator (-).
• Question 7:

## CPP

 `#include ` `using` `namespace` `std;` `int` `Add(``int` `X, ``int` `Y, ``int` `Z)` `{` `    ``return` `X + Y;` `}` `double` `Add(``double` `X, ``double` `Y, ``double` `Z)` `{` `    ``return` `X + Y;` `}` `int` `main()` `{` `    ``cout << Add(5, 6);` `    ``cout << Add(5.5, 6.6);` `    ``return` `0;` `}`

• Output:

`Compile time Error!`
• Explanation: Constant variables are those whose value can’t be changed throughout the execution. ++p statement try to change the value hence compiler will raise an error.
• Question 8:

## CPP

 `#include ` `using` `namespace` `std;` `#define PR(id) cout << "The value of " #id " is " << id` `int` `main()` `{` `    ``int` `i = 10;` `    ``PR(i);` `    ``return` `0;` `}`

• Output:

`ABCDEFGHIJ`
• Explanation: Each time we are assigning 65 + i. In first iteration i = 0 and 65 is assigned. So it will print from A to J.

• Question 9:

## CPP

• Output:

`Compile time error!`
• Explanation: Here we want to add two element but in the given functions we take 3 arguments.So compiler doesn’t get the required function(function with 2 arguments)
• Question 10:

## CPP

 `#include ` `using` `namespace` `std;` `#define PR(id) cout << "The value of " #id " is " << id` `int` `main()` `{` `    ``int` `i = 10;` `    ``PR(i);` `    ``return` `0;` `}`

• Output:

`The value of i is 10`
• Explanation: In this program, we are just printing the declared value through a macro. Carefully observe that in macro there is no semicolon(;) used as a termination statement.

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