Given a positive integer N, find out how many positive integers strictly less than N have the same number of set bits as N.
Input : 8 Output :3 Explanation: Binary representation of 8 : 1000, so number of set bits in 8 is 1. So the integers less than 8 with same number of set bits are : 4, 2, 1 Input :1 Output :0 Input :4 Output :2
1. Using __builtin_popcount() inbuilt function, count set bits in N and store into a temp variable 2. Iterate from n-1 to 1 and also count set bits in i using __builtin_popcount() function 3. Now, compare temp with __builtin_popcount(i) 4. If both are equal then increment counter variable 5. Return counter
Below is the implementation of above approach.
- Check if bits of a number has count of consecutive set bits in increasing order
- Toggle bits of a number except first and last bits
- Maximize a given unsigned number number by swapping bits at it's extreme positions.
- Check if a number has same number of set and unset bits
- Set all odd bits of a number
- Set all even bits of a number
- Toggle all even bits of a number
- Toggle all odd bits of a number
- For every set bit of a number toggle bits of other
- Change all even bits in a number to 0
- Largest number less than X having at most K set bits
- Toggle all the bits of a number except k-th bit.
- Check if all bits of a number are set
- Set all the bits in given range of a number
- Toggle first and last bits of a number
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