# Minimum number of letters needed to make a total of n

Given an integer n and let a = 1, b = 2, c= 3, ….., z = 26. The task is to find the minimum number of letters needed to make a total of n.

Examples:

Input: n = 48
Output: 2
48 can be written as z + v, where z = 26 and v = 22

Input: n = 23
Output: 1

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: There are 2 possible cases:

1. If n is divisible by 26 then the answer will be n / 26.
2. If n is not divisible by 26 then the answer will be (n / 26) + 1.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `// Function to return the minimum letters ` `// required to make a total of n ` `int` `minLettersNeeded(``int` `n) ` `{ ` `    ``if` `(n % 26 == 0) ` `        ``return` `(n / 26); ` `    ``else` `        ``return` `((n / 26) + 1); ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `n = 52; ` `    ``cout << minLettersNeeded(n); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation of the approach ` `class` `GFG { ` ` `  `    ``// Function to return the minimum letters ` `    ``// required to make a total of n ` `    ``static` `int` `minLettersNeeded(``int` `n) ` `    ``{ ` `        ``if` `(n % ``26` `== ``0``) ` `            ``return` `(n / ``26``); ` `        ``else` `            ``return` `((n / ``26``) + ``1``); ` `    ``} ` ` `  `    ``// Driver code ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``int` `n = ``52``; ` `        ``System.out.print(minLettersNeeded(n)); ` `    ``} ` `} `

## Python3

 `  `  `# Python3 implementation of the approach ` ` `  `# Function to return the minimum letters ` `# required to make a total of n ` `def` `minLettersNeeded(n):  ` ` `  `    ``if` `n ``%` `26` `=``=` `0``: ` `        ``return` `(n``/``/``26``) ` `    ``else``: ` `        ``return` `((n``/``/``26``) ``+` `1``) ` ` `  `# Driver code ` `n ``=` `52` `print``(minLettersNeeded(n)) `

## C#

 `// C# implementation of the approach ` `using` `System; ` `class` `GFG { ` ` `  `    ``// Function to return the minimum letters ` `    ``// required to make a total of n ` `    ``static` `int` `minLettersNeeded(``int` `n) ` `    ``{ ` `        ``if` `(n % 26 == 0) ` `            ``return` `(n / 26); ` `        ``else` `            ``return` `((n / 26) + 1); ` `    ``} ` ` `  `    ``// Driver code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `n = 52; ` `        ``Console.Write(minLettersNeeded(n)); ` `    ``} ` `} `

## PHP

 ` `

Output:

```2
```

Time Complexity: O(1)

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