Minimum number of letters needed to make a total of n
Given an integer n and let a = 1, b = 2, c= 3, ….., z = 26. The task is to find the minimum number of letters needed to make a total of n.
Examples:
Input: n = 48
Output: 2
48 can be written as z + v, where z = 26 and v = 22
Input: n = 23
Output: 1
Approach: There are 2 possible cases:
- If n is divisible by 26 then the answer will be n / 26.
- If n is not divisible by 26 then the answer will be (n / 26) + 1.
Below is the implementation of the above approach:
C++
// C++ implementation of the approach #include <bits/stdc++.h> using namespace std; // Function to return the minimum letters // required to make a total of n int minLettersNeeded(int n) { if (n % 26 == 0) return (n / 26); else return ((n / 26) + 1); } // Driver code int main() { int n = 52; cout << minLettersNeeded(n); return 0; } |
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Java
// Java implementation of the approach class GFG { // Function to return the minimum letters // required to make a total of n static int minLettersNeeded(int n) { if (n % 26 == 0) return (n / 26); else return ((n / 26) + 1); } // Driver code public static void main(String args[]) { int n = 52; System.out.print(minLettersNeeded(n)); } } |
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Python3
# Python3 implementation of the approach # Function to return the minimum letters # required to make a total of n def minLettersNeeded(n): if n % 26 == 0: return (n//26) else: return ((n//26) + 1) # Driver code n = 52print(minLettersNeeded(n)) |
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C#
// C# implementation of the approach using System; class GFG { // Function to return the minimum letters // required to make a total of n static int minLettersNeeded(int n) { if (n % 26 == 0) return (n / 26); else return ((n / 26) + 1); } // Driver code public static void Main() { int n = 52; Console.Write(minLettersNeeded(n)); } } |
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PHP
<?php // PHP implementation of the approach // Function to return the minimum // letters required to make a // total of n function minLettersNeeded($n) { if ($n % 26 == 0) return floor(($n / 26)); else return floor(($n / 26) + 1); } // Driver code $n = 52; echo minLettersNeeded($n); // This code is contirbuted by Ryuga ?> |
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Output:
2
Time Complexity: O(1)
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Improved By : AnkitRai01
