Given a positive number N. The task is to find maximum sum of distinct numbers such that the LCM of all these numbers is equal to N.
Input : 2 Output : 3 The distinct numbers you can have are just 1 and 2 and their sum is equal to 3. Input : 5 Output : 6
As the LCM of all the numbers is N. So all the numbers must be the divisors of N and all the numbers are distinct so answer must be the sum of all the divisors of N. To find all the divisors efficiently refer to article https://www.geeksforgeeks.org/find-all-divisors-of-a-natural-number-set-2/
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