Given a natural number n, print all distinct divisors of it.
Input : n = 10 Output: 1 2 5 10 Input: n = 100 Output: 1 2 4 5 10 20 25 50 100 Input: n = 125 Output: 1 5 25 125
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Find all divisors of a natural number | Set 1
In the above post, we had found a way to find all the divisors in O(sqrt(n)) .
However there is still a minor problem in the solution, can you guess?
Yes! the output is not in a sorted fashion which we had got using brute-force technique.
How to print the output in sorted order?
If we observe the output which we had got, we can analyze that the divisors are printed in a zig-zag fashion (small, large pairs). Hence if we store half of them then we can print then in a sorted order.
Below is a implementation for the same:
The divisors of 100 are: 1 2 4 5 10 20 25 50 100
Time Complexity : O(sqrt(n))
Auxiliary Space : O(sqrt(n))
This article is contributed by Ashutosh Kumar. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
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