# Maximize a given unsigned number number by swapping bits at it’s extreme positions.

Given a number maximize it by swapping bits at it’s extreme positions i.e. at first and last position, second and second last position and so on. **Examples:**

Input : 4 (0000...0100) Output : 536870912 (0010...0000) In the above example swapped 3rd and 3rd last bit to maximize the given unsigned number. Input : 12 (00000...1100) Output : 805306368 (0011000...0000) In the above example 3rd and 3rd last bit and 4th and 4th last bit are swapped to maximize the given unsigned number.

**Naive Approach: ****1.** Convert the number into it’s bit representation and store it’s bit representation in an array.**2.** Traverse the array from both ends, if the less significant bit of the bit representation is greater than the more significant bit i.e. if less significant bit is 1 and more significant bit is 0 then swap them else take no action.**3.** Convert the obtained binary representation back to the number.**Efficient Approach: ****1.** Create a copy of the original number because the original number would be modified, iteratively obtain the bits at the extreme positions.**2.** If less significant bit is 1 and more significant bit is 0 then swap the bits in the bit from only, continue the process until less significant bit’s position is less than more significant bit’s position.**3.** Display the maximized number.

## C++

`// C++ program to find maximum number by` `// swapping extreme bits.` `#include <bits/stdc++.h>` `using` `namespace` `std;` `#define ull unsigned long long int` `ull findMax(ull num)` `{` ` ` `ull num_copy = num;` ` ` `/* Traverse bits from both extremes */` ` ` `int` `j = ` `sizeof` `(unsigned ` `long` `long` `int` `) * 8 - 1;` ` ` `int` `i = 0;` ` ` `while` `(i < j) {` ` ` `// Obtaining i-th and j-th bits` ` ` `int` `m = (num_copy >> i) & 1;` ` ` `int` `n = (num_copy >> j) & 1;` ` ` `/* Swapping the bits if lesser significant` ` ` `is greater than higher significant` ` ` `bit and accordingly modifying the number */` ` ` `if` `(m > n) {` ` ` `int` `x = (1 << i | 1 << j);` ` ` `num = num ^ x;` ` ` `}` ` ` `i++;` ` ` `j--;` ` ` `}` ` ` `return` `num;` `}` `// Driver code` `int` `main()` `{` ` ` `ull num = 4;` ` ` `cout << findMax(num);` ` ` `return` `0;` `}` |

## Java

`// Java program to find maximum number by` `// swapping extreme bits.` `class` `GFG {` ` ` `static` `int` `findMax(` `int` `num) {` ` ` `byte` `size_of_int = ` `4` `;` ` ` `int` `num_copy = num;` ` ` `/* Traverse bits from both extremes */` ` ` `int` `j = size_of_int * ` `8` `- ` `1` `;` ` ` `int` `i = ` `0` `;` ` ` `while` `(i < j) {` ` ` `// Obtaining i-th and j-th bits` ` ` `int` `m = (num_copy >> i) & ` `1` `;` ` ` `int` `n = (num_copy >> j) & ` `1` `;` ` ` `/* Swapping the bits if lesser significant` ` ` `is greater than higher significant` ` ` `bit and accordingly modifying the number */` ` ` `if` `(m > n) {` ` ` `int` `x = (` `1` `<< i | ` `1` `<< j);` ` ` `num = num ^ x;` ` ` `}` ` ` `i++;` ` ` `j--;` ` ` `}` ` ` `return` `num;` ` ` `}` ` ` `// Driver code` ` ` `static` `public` `void` `main(String[] args) {` ` ` `int` `num = ` `4` `;` ` ` `System.out.println(findMax(num));` ` ` `}` `}` `// This code is contributed by 29AjayKumar` |

## Python 3

`# Python 3 program to find maximum number` `# by swapping extreme bits.` `def` `findMax( num):` ` ` `num_copy ` `=` `num` ` ` `# Traverse bits from both extremes` ` ` `j ` `=` `4` `*` `8` `-` `1` `;` ` ` `i ` `=` `0` ` ` `while` `(i < j) :` ` ` `# Obtaining i-th and j-th bits` ` ` `m ` `=` `(num_copy >> i) & ` `1` ` ` `n ` `=` `(num_copy >> j) & ` `1` ` ` `# Swapping the bits if lesser significant` ` ` `# is greater than higher significant` ` ` `# bit and accordingly modifying the number` ` ` `if` `(m > n) :` ` ` `x ` `=` `(` `1` `<< i | ` `1` `<< j)` ` ` `num ` `=` `num ^ x` ` ` `i ` `+` `=` `1` ` ` `j ` `-` `=` `1` ` ` `return` `num` `# Driver code` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` ` ` `num ` `=` `4` ` ` `print` `(findMax(num))` `# This code is contributed by ita_c` |

## C#

` ` `// C# program to find maximum number by` `// swapping extreme bits.` `using` `System;` `public` `class` `GFG {` ` ` ` ` `static` `int` `findMax(` `int` `num) {` ` ` `byte` `size_of_int = 4;` ` ` `int` `num_copy = num;` ` ` ` ` `/* Traverse bits from both extremes */` ` ` `int` `j = size_of_int * 8 - 1;` ` ` `int` `i = 0;` ` ` `while` `(i < j) {` ` ` ` ` `// Obtaining i-th and j-th bits` ` ` `int` `m = (num_copy >> i) & 1;` ` ` `int` `n = (num_copy >> j) & 1;` ` ` ` ` `/* Swapping the bits if lesser significant` ` ` `is greater than higher significant` ` ` `bit and accordingly modifying the number */` ` ` `if` `(m > n) {` ` ` `int` `x = (1 << i | 1 << j);` ` ` `num = num ^ x;` ` ` `}` ` ` ` ` `i++;` ` ` `j--;` ` ` `}` ` ` `return` `num;` ` ` `}` ` ` `// Driver code` ` ` `static` `public` `void` `Main() {` ` ` `int` `num = 4;` ` ` `Console.Write(findMax(num));` ` ` `}` `}` ` ` `// This code is contributed by 29AjayKumar` |

## Javascript

`<script>` `// JavaScript program to find maximum number by` `// swapping extreme bits.` `function` `findMax(num)` `{` ` ` `let num_copy = num;` ` ` `/* Traverse bits from both extremes */` ` ` `let j = 4 * 8 - 1;` ` ` `let i = 0;` ` ` `while` `(i < j) {` ` ` `// Obtaining i-th and j-th bits` ` ` `let m = (num_copy >> i) & 1;` ` ` `let n = (num_copy >> j) & 1;` ` ` `/* Swapping the bits if lesser significant` ` ` `is greater than higher significant` ` ` `bit and accordingly modifying the number */` ` ` `if` `(m > n) {` ` ` `let x = (1 << i | 1 << j);` ` ` `num = num ^ x;` ` ` `}` ` ` `i++;` ` ` `j--;` ` ` `}` ` ` `return` `num;` `}` `// Driver code` ` ` `let num = 4;` ` ` `document.write(findMax(num));` `// This code is contributed by Manoj.` `</script>` |

**Output:**

536870912

This article is contributed by **Aditya Gupta**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the **DSA Self Paced Course** at a student-friendly price and become industry ready. To complete your preparation from learning a language to DS Algo and many more, please refer **Complete Interview Preparation Course****.**

In case you wish to attend **live classes **with experts, please refer **DSA Live Classes for Working Professionals **and **Competitive Programming Live for Students**.