Given an array arr[] of distinct elements, the task is to rearrange the array such that it is lexicographically smallest and of the form arr[0] > arr[1] < arr[2] > arr[3] < …
Examples:
Input: arr[] = {3, 2, 1, 4, 5}
Output: 2 1 4 3 5
Input: arr[] = {10, 22}
Output: 22 10
Approach: In order to get the lexicographically smallest array, we can choose the minimum element as the first element but that will not satisfy the condition where the first element has to be strictly greater than the second element.
Now, the second-best choice is to choose the second minimum from the array and the only element which is smaller than it is the smallest element which will be the second element of the array.
Apply the same process for the rest of the array elements, choose the second minimum of the remaining elements and then choose the minimum for every two consecutive positions which can be obtained by first sorting the given array then swapping every two consecutive elements.
Below is the implementation of the above approach:
C++
#include <bits/stdc++.h>
using namespace std;
void printArr( int arr[], int n)
{
for ( int i = 0; i < n; i++) {
cout << arr[i] << " " ;
}
}
void smallestArr( int arr[], int n)
{
sort(arr, arr + n);
for ( int i = 0; i + 1 < n; i = i + 2) {
swap(arr[i], arr[i + 1]);
}
printArr(arr, n);
}
int main()
{
int arr[] = { 3, 2, 1, 4, 5 };
int n = sizeof (arr) / sizeof (arr[0]);
smallestArr(arr, n);
return 0;
}
|
Java
import java.util.Arrays;
class GFG
{
static void printArr( int [] arr, int n)
{
for ( int i = 0 ; i < n; i++)
System.out.print(arr[i] + " " );
}
static void smallestArr( int [] arr, int n)
{
Arrays.sort(arr);
for ( int i = 0 ; i + 1 < n; i = i + 2 )
{
int temp = arr[i];
arr[i] = arr[i + 1 ];
arr[i + 1 ] = temp;
}
printArr(arr, n);
}
public static void main(String[] args)
{
int [] arr = { 3 , 2 , 1 , 4 , 5 };
int n = arr.length;
smallestArr(arr, n);
}
}
|
Python3
def printArr(arr, n):
for i in range (n):
print (arr[i], end = " " );
def smallestArr(arr, n):
arr.sort();
for i in range ( 0 , n - 1 , 2 ):
temp = arr[i];
arr[i] = arr[i + 1 ];
arr[i + 1 ] = temp;
printArr(arr, n);
if __name__ = = '__main__' :
arr = [ 3 , 2 , 1 , 4 , 5 ];
n = len (arr);
smallestArr(arr, n);
|
C#
using System;
class GFG
{
static void printArr( int [] arr, int n)
{
for ( int i = 0; i < n; i++)
Console.Write(arr[i] + " " );
}
static void smallestArr( int [] arr, int n)
{
Array.Sort(arr);
for ( int i = 0; i + 1 < n; i = i + 2)
{
int temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
}
printArr(arr, n);
}
public static void Main(String[] args)
{
int [] arr = { 3, 2, 1, 4, 5 };
int n = arr.Length;
smallestArr(arr, n);
}
}
|
PHP
<?php
function printArr( $arr , $n )
{
for ( $i = 0; $i < $n ; $i ++)
{
echo $arr [ $i ];
echo " " ;
}
}
function smallestArr( $arr , $n )
{
sort( $arr );
for ( $i = 0; $i + 1 < $n ; $i = $i + 2)
{
$temp = $arr [ $i ];
$arr [ $i ] = $arr [ $i + 1];
$arr [ $i + 1] = $temp ;
}
printArr( $arr , $n );
}
$arr = array ( 3, 2, 1, 4, 5 );
$n = count ( $arr );
smallestArr( $arr , $n );
?>
|
Javascript
function printArr(arr, n)
{
for ( var i = 0; i < n; i++)
document.write(arr[i] + " " );
}
function smallestArr( arr, n)
{
arr.sort();
for ( var i = 0; i + 1 < n; i = i + 2)
{
var temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
}
printArr(arr, n);
}
var arr = [ 3, 2, 1, 4, 5 ] ;
var n = arr.length;
smallestArr(arr, n);
|
Time Complexity: O(nlogn)
Auxiliary Space: O(1)