Given a positive number **k** and an undirected graph of **N** nodes, numbered from 0 to N-1, each having a weight associated with it. Note that this is different from a normal weighted graph where every edge has a weight.

For each node, if we sort the nodes (according to their weights), which are directly connected to it, in decreasing order, then what will be the number of the node at the **kth** position. Print kth node number(not weight) for each node and if it does not exist, print -1.

Examples:

Input :N = 3, k = 2, wt[] = { 2, 4, 3 }. edge 1: 0 2 edge 2: 0 1 edge 3: 1 2Output :2 0 0 Graph: 0 (weight 2) / \ / \ 1-----2 (weight 4) (weight 3) For node0, sorted (decreasing order) nodes according to their weights are node 1(weight 4), node 2(weight 3). The node at 2nd position for node 0 is node 2. For node1, sorted (decreasing order) nodes according to their weight are node 2(weight 3), node 0(weight 2). The node at 2nd position for node 1 is node 0. For node2, sorted (decreasing order) nodes according to their weight are node 1(weight 4), node 0(weight 2). The node at 2nd position for node 2 is node 0.

The idea is to sort Adjacency List of each node on the basis of adjacent node weights.

First, create Adjacency List for all the nodes. Now for each node, all the nodes which are directly connected to it stored in a list. In adjacency list, store the nodes along with their weights.

Now, for each node sort the weights of all nodes which are directly connected to it in reverse order, and then print the node number which is at kth position in the list of each node.

Below is C++ implementation of this approach:

`// C++ program to find Kth node weight after s ` `// orting of nodes directly connected to a node. ` `#include<bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Print Kth node number for each node after sorting ` `// connected node according to their weight. ` `void` `printkthnode(vector< pair<` `int` `, ` `int` `> > adj[], ` ` ` `int` `wt[], ` `int` `n, ` `int` `k) ` `{ ` ` ` `// Sort Adjacency List of all node on the basis ` ` ` `// of its weight. ` ` ` `for` `(` `int` `i = 0; i < n; i++) ` ` ` `sort(adj[i].begin(), adj[i].end()); ` ` ` ` ` `// Printing Kth node for each node. ` ` ` `for` `(` `int` `i = 0; i < n; i++) ` ` ` `{ ` ` ` `if` `(adj[i].size() >= k) ` ` ` `cout << adj[i][adj[i].size() - k].second; ` ` ` `else` ` ` `cout << ` `"-1"` `; ` ` ` `} ` `} ` ` ` `// Driven Program ` `int` `main() ` `{ ` ` ` `int` `n = 3, k = 2; ` ` ` `int` `wt[] = { 2, 4, 3 }; ` ` ` ` ` `// Making adjacency list, storing the nodes ` ` ` `// along with their weight. ` ` ` `vector< pair<` `int` `, ` `int` `> > adj[n+1]; ` ` ` ` ` `adj[0].push_back(make_pair(wt[2], 2)); ` ` ` `adj[2].push_back(make_pair(wt[0], 0)); ` ` ` ` ` `adj[0].push_back(make_pair(wt[1], 1)); ` ` ` `adj[1].push_back(make_pair(wt[0], 0)); ` ` ` ` ` `adj[1].push_back(make_pair(wt[2], 2)); ` ` ` `adj[2].push_back(make_pair(wt[1], 1)); ` ` ` ` ` `printkthnode(adj, wt, n, k); ` ` ` `return` `0; ` `} ` |

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Output:

2 0 0

This article is contributed by **Anuj Chauhan**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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