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Java Integer compareTo() method
  • Last Updated : 05 Dec, 2018

The compareTo() method of Integer class of java.lang package compares two Integer objects numerically and returns the value 0 if this Integer is equal to the argument Integer; a value less than 0 if this Integer is numerically less than the argument Integer; and a value greater than 0 if this Integer is numerically greater than the argument Integer (signed comparison).

Syntax :

public int compareTo(Integer anotherInt)
Parameter :
anotherInt- : the Integer to be compared.
Return :
- This method returns the value 0 if this Integer is 
equal to the argument Integer; 
- a value less than 0 if this Integer is 
numerically less than the argument Integer; 
- and a value greater than 0 if this Integer is
numerically greater than the argument Integer
(signed comparison).

Example : To show working of java.lang.Integer.compareTo() method.




// Java program to demonstrate working
// of java.lang.Integer.compareTo() method
import java.lang.Integer;
  
class Gfg {
  
    // driver code
    public static void main(String args[])
    {
        Integer a = new Integer(10);
        Integer b = new Integer(20);
  
        // as 10 less than 20, Output will be a value less than zero
        System.out.println(a.compareTo(b));
  
        Integer x = new Integer(30);
        Integer y = new Integer(30);
  
        // as 30 equals 30, Output will be zero
        System.out.println(x.compareTo(y));
  
        Integer w = new Integer(15);
        Integer z = new Integer(8);
  
        // as 15 is greater than 8, Output will be a value greater than zero
        System.out.println(w.compareTo(z));
    }
}

Output:

-1
0
1

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