BigInteger compareTo() Method in Java
The java.math.BigInteger.compareTo(BigInteger value) method Compares this BigInteger with the BigInteger passed as the parameter.
Syntax:
public int compareTo(BigInteger val)
Parameter: This method accepts a single mandatory parameter val which is the BigInteger to compare with BigInteger object.
Returns: This method returns the following:
- 0: if the value of this BigInteger is equal to that of the BigInteger object passed as a parameter.
- 1: if the value of this BigInteger is greater than that of the BigInteger object passed as a parameter.
- -1: if the value of this BigInteger is less than that of the BigInteger object passed as a parameter.
Examples:
Input: BigInteger1=2345, BigInteger2=7456 Output: -1 Explanation: BigInteger1.compareTo(BigInteger2)=-1. Input: BigInteger1=9834, BigInteger2=7456 Output: 1 Explanation: BigInteger1.compareTo(BigInteger2)=1.
Example 1: Below programs illustrate compareTo() method of BigInteger class when both BigIntegers are equal
// Java program to demonstrate // compareTo() method of BigInteger import java.math.BigInteger; public class GFG { public static void main(String[] args) { // Creating 2 BigInteger objects BigInteger b1, b2; b1 = new BigInteger("321456"); b2 = new BigInteger("321456"); // apply compareTo() method int comparevalue = b1.compareTo(b2); // print result if (comparevalue == 0) { System.out.println("BigInteger1 " + b1 + " and BigInteger2 " + b2 + " are equal"); } else if (comparevalue == 1) { System.out.println("BigInteger1 " + b1 + " is greater than BigInteger2 " + b2); } else { System.out.println("BigInteger1 " + b1 + " is lesser than BigInteger2 " + b2); } }} |
Output:
BigInteger1 321456 and BigInteger2 321456 are equal
Example 2: when BigInteger1 is greater than BigInteger2
// Java program to demonstrate // compareTo() method of BigInteger import java.math.BigInteger; public class GFG { public static void main(String[] args) { // Creating 2 BigInteger objects BigInteger b1, b2; b1 = new BigInteger("654321"); b2 = new BigInteger("321456"); // apply compareTo() method int comparevalue = b1.compareTo(b2); // print result if (comparevalue == 0) { System.out.println("BigInteger1 " + b1 + " and BigInteger2 " + b2 + " are equal"); } else if (comparevalue == 1) { System.out.println("BigInteger1 " + b1 + " is greater than BigInteger2 " + b2); } else { System.out.println("BigInteger1 " + b1 + " is lesser than BigInteger2 " + b2); } }} |
Output:
BigInteger1 654321 is greater than BigInteger2 321456
Example 3: When BigInteger1 is lesser than BigInteger2
// Java program to demonstrate // compareTo() method of BigInteger import java.math.BigInteger; public class GFG { public static void main(String[] args) { // Creating 2 BigInteger objects BigInteger b1, b2; b1 = new BigInteger("321456"); b2 = new BigInteger("564321"); // apply compareTo() method int comparevalue = b1.compareTo(b2); // print result if (comparevalue == 0) { System.out.println("BigInteger1 " + b1 + " and BigInteger2 " + b2 + " are equal"); } else if (comparevalue == 1) { System.out.println("BigInteger1 " + b1 + " is greater than BigInteger2 " + b2); } else { System.out.println("BigInteger1 " + b1 + " is lesser than BigInteger2 " + b2); } }} |
Output:
BigInteger1 321456 is lesser than BigInteger2 564321
Reference:
BigInteger CompareTo() Docs
