How to store words in an array in C?
We all know how to store a word or String, how to store characters in an array, etc. This article will help you understand how to store words in an array in C.
To store the words, a 2-D char array is required. In this 2-D array, each row will contain a word each. Hence the rows will denote the index number of the words and the column number will denote the particular character in that word.
- Direct initialization: In this method, the words are already known and the 2-D char array is created with these words directly.
Syntax for Direct initialization:
char array[][20] = {"Geek1", "Geek2", "Geek3", ..."};
Syntax for accessing a word:
Lets say we need to fetch the ith word:
array[i]
Below is the implementation of the above approach:
#include <stdio.h>
int main()
{
int i;
char array[][20] = { "Geek1" , "Geek2" , "Geek3" };
for (i = 0; i < 3; i++)
printf ( "%s\n" , array[i]);
return 0;
}
|
Output:
Geek1
Geek2
Geek3
- By taking input from user: In this method, the number of words and words are given by the user and we have to create and map the 2-D char array for each word.
Syntax:
// Declaration of 2-D char array
// where n is the number of words
char array[n][20];
// Initialization of 2-D char array
for (i = 0; i < n; i++)
scanf("%s", array[i]);
Syntax for accessing a word:
Lets say we need to fetch the ith word:
array[i]
Below is the implementation of the above approach:
#include <stdio.h>
int main()
{
int i;
int n = 3;
char array[n][20];
for (i = 0; i < 3; i++)
scanf ( "%s" , array[i]);
for (i = 0; i < 3; i++)
printf ( "%s\n" , array[i]);
return 0;
}
|
Input:
Geek1
Geek2
Geek3
Output:
Geek1
Geek2
Geek3
Last Updated :
18 Oct, 2019
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