Given a Linked List. The Linked List is in alternating ascending and descending orders. Sort the list efficiently.
Input List: 10 -> 40 -> 53 -> 30 -> 67 -> 12 -> 89 -> NULL Output List: 10 -> 12 -> 30 -> 43 -> 53 -> 67 -> 89 -> NULL Input List: 1 -> 4 -> 3 -> 2 -> 5 -> NULL Output List: 1 -> 2 -> 3 -> 4 -> 5 -> NULL
Approach: The basic idea is to apply merge sort on linked list.
The implementation is discussed in this article: Merge Sort for linked List.
- Time Complexity: The merge sort of linked list takes O(n log n) time. In the merge sort tree the height is log n. Sorting each level will take O(n) time. So time complexity is O(n log n).
- Auxiliary Space: O(n log n), In the merge sort tree the height is log n. Storing each level will take O(n) space. So space complexity is O(n log n).
- Separate two lists.
- Reverse the one with descending order
- Merge both lists.
Below are the implementations of above algorithm.
Given Linked List is 10 40 53 30 67 12 89 Sorted Linked List is 10 12 30 40 53 67 89
- Time Complexity: O(n).
One traversal is needed to separate the list and reverse them. The merging of sorted lists takes O(n) time.
- Auxiliary Space: O(1).
No extra space is required.
Thanks to Gaurav Ahirwar for suggesting this method.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above
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