Given a form and the task is to check form submitted successfully or not. Use the PHP program for the backend to check form submission and HTML and CSS to create the form as frontend.
if (!empty($_POST)) if (isset($_POST['submit']))
Use these two statements to check whether the form submitted successfully or not.
Note: To run this program use localhost server like WAMP or XAMPP.
Step 1: Create a simple form using HTML and CSS.
In this step, make an html form first to check whether it is submitted properly or not. So it is just basic programming to make a form using form tag. Use the action attribute to send the request to another PHP file. The method is used to GET the information or POST the information as entered in the form.
Step 2: Create PHP file for POST method
Use isset() method in PHP to test the form is submitted successfully or not. In the code, use isset() function to check $_POST[‘submit’] method. Remember in place of submit define the name of submit button. After clicking on submit button this action will work as POST method.
Final output on the localhost:
Without using separate PHP file: Without using a separate file, written an HTML code in which to specify the code for PHP action in script tag as we did in this demonstration. Both of these codes display the same output but their implementation is different.
Output on the localhost:
- HTML | form Tag
- PHP Full Form
- URL full form
- AngularJS | Form Validation
- HTML | DOM Form name Property
- HTML | Design Form
- How to get access to the containing form of an input?
- HTML | DOM Form Object
- AngularJS | ng-form Directive
- HTML | form Attribute
- HTML | <form> name Attribute
- HTML full form
- HTML | <form> novalidate Attribute
- HTML | DOM Form noValidate Property
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