# Given count of digits 1, 2, 3, 4, find the maximum sum possible

Given the count of digits 1, 2, 3, 4. Using these digits you are allowed to only form numbers 234 and 12. The task is to find the maximum possible sum that can be obtained after forming the numbers.

**Note**: The aim is only to maximize the sum, even if some of the digits left unused.

**Examples:**

Input :c1 = 5, c2 = 2, c3 = 3, c4 = 4Output :468Explanation :We can form two 234sInput :c1 = 5, c2 = 3, c3 = 1, c4 = 5Output :258Explanation :We can form one 234 and two 12s

**Approach** : An efficient approach is to first try to make 234’s. The possible number of 234s are minimum of c2, c3, c4. After this, with remaining 1’s and 2’s try to form 12s.

Below is the implementation of the above approach :

## C++

`// CPP program to maximum possible sum ` ` ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to find the maximum possible sum ` `int` `Maxsum(` `int` `c1, ` `int` `c2, ` `int` `c3, ` `int` `c4) ` `{ ` ` ` `// To store required sum ` ` ` `int` `sum = 0; ` ` ` ` ` `// Number of 234's can be formed ` ` ` `int` `two34 = min(c2, min(c3, c4)); ` ` ` ` ` `// Sum obtained with 234s ` ` ` `sum = two34 * 234; ` ` ` ` ` `// Remaining 2's ` ` ` `c2 -= two34; ` ` ` ` ` `// Sum obtained with 12s ` ` ` `sum += min(c2, c1) * 12; ` ` ` ` ` `// Return the requied sum ` ` ` `return` `sum; ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `int` `c1 = 5, c2 = 2, c3 = 3, c4 = 4; ` ` ` ` ` `cout << Maxsum(c1, c2, c3, c4); ` ` ` ` ` `return` `0; ` `} ` |

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## Java

`// Java program to maximum possible sum ` `class` `GFG ` `{ ` ` ` `// Function to find the maximum possible sum ` `static` `int` `Maxsum(` `int` `c1, ` `int` `c2, ` `int` `c3, ` `int` `c4) ` `{ ` ` ` `// To store required sum ` ` ` `int` `sum = ` `0` `; ` ` ` ` ` `// Number of 234's can be formed ` ` ` `int` `two34 = Math.min(c2,Math.min(c3, c4)); ` ` ` ` ` `// Sum obtained with 234s ` ` ` `sum = two34 * ` `234` `; ` ` ` ` ` `// Remaining 2's ` ` ` `c2 -= two34; ` ` ` ` ` `// Sum obtained with 12s ` ` ` `sum +=Math.min(c2, c1) * ` `12` `; ` ` ` ` ` `// Return the requied sum ` ` ` `return` `sum; ` `} ` ` ` `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` ` ` `int` `c1 = ` `5` `, c2 = ` `2` `, c3 = ` `3` `, c4 = ` `4` `; ` ` ` ` ` `System.out.println(Maxsum(c1, c2, c3, c4)); ` `} ` `} ` ` ` `// This code is contributed by Code_Mech. ` |

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## Python3

`# Python3 program to maximum possible sum ` ` ` `# Function to find the maximum ` `# possible sum ` `def` `Maxsum(c1, c2, c3, c4): ` ` ` ` ` `# To store required sum ` ` ` `sum` `=` `0` ` ` ` ` `# Number of 234's can be formed ` ` ` `two34 ` `=` `min` `(c2, ` `min` `(c3, c4)) ` ` ` ` ` `# Sum obtained with 234s ` ` ` `sum` `=` `two34 ` `*` `234` ` ` ` ` `# Remaining 2's ` ` ` `c2 ` `-` `=` `two34 ` ` ` `sum` `+` `=` `min` `(c2, c1) ` `*` `12` ` ` ` ` `# Return the requied sum ` ` ` `return` `sum` ` ` `# Driver Code ` `c1 ` `=` `5` `; c2 ` `=` `2` `; c3 ` `=` `3` `; c4 ` `=` `4` `print` `(Maxsum(c1, c2, c3, c4)) ` ` ` `# This code is contributed by Shrikant13 ` |

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## C#

// C# program to maximum possible sum

using System;

class GFG

{

// Function to find the maximum possible sum

static int Maxsum(int c1, int c2, int c3, int c4)

{

// To store required sum

int sum = 0;

// Number of 234’s can be formed

int two34 = Math.Min(c2, Math.Min(c3, c4));

// Sum obtained with 234s

sum = two34 * 234;

// Remaining 2’s

c2 -= two34;

// Sum obtained with 12s

sum +=Math.Min(c2, c1) * 12;

// Return the requied sum

return sum;

}

// Driver code

public static void Main()

{

int c1 = 5, c2 = 2, c3 = 3, c4 = 4;

Console.WriteLine(Maxsum(c1, c2, c3, c4));

}

}

// This code is contributed

// by Akanksha Rai

## PHP

`<?php ` `// PHP program to maximum possible sum ` ` ` `// Function to find the maximum possible sum ` `function` `Maxsum(` `$c1` `, ` `$c2` `, ` `$c3` `, ` `$c4` `) ` `{ ` ` ` `// To store required sum ` ` ` `$sum` `= 0; ` ` ` ` ` `// Number of 234's can be formed ` ` ` `$two34` `= min(` `$c2` `, min(` `$c3` `, ` `$c4` `)); ` ` ` ` ` `// Sum obtained with 234s ` ` ` `$sum` `= ` `$two34` `* 234; ` ` ` ` ` `// Remaining 2's ` ` ` `$c2` `-= ` `$two34` `; ` ` ` ` ` `// Sum obtained with 12s ` ` ` `$sum` `+= min(` `$c2` `, ` `$c1` `) * 12; ` ` ` ` ` `// Return the requied sum ` ` ` `return` `$sum` `; ` `} ` ` ` `// Driver code ` `$c1` `= 5; ` `$c2` `= 2; ` `$c3` `= 3; ` `$c4` `= 4; ` ` ` `echo` `Maxsum(` `$c1` `, ` `$c2` `, ` `$c3` `, ` `$c4` `); ` ` ` `// This code is contributed by Ryuga ` `?> ` |

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**Output:**

468

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