Given an array of pairs, find all symmetric pairs in it
Two pairs (a, b) and (c, d) are said to be symmetric if c is equal to b and a is equal to d. For example, (10, 20) and (20, 10) are symmetric. Given an array of pairs find all symmetric pairs in it.
It may be assumed that the first elements of all pairs are distinct.
Example:
Input: arr[] = {{11, 20}, {30, 40}, {5, 10}, {40, 30}, {10, 5}}
Output: Following pairs have symmetric pairs
(30, 40)
(5, 10) We strongly recommend you to minimize your browser and try this yourself first.
A Simple Solution is to go through every pair, and check every other pair for symmetric. This solution requires O(n2) time.
A Better Solution is to use sorting. Sort all pairs by the first element. For every pair, do a binary search for the second element in the given array, i.e., check if the second element of this pair exists as the first element in the array. If found, then compare the first element of pair with the second element. Time Complexity of this solution is O(nLogn).
An Efficient Solution is to use Hashing. The first element of pair is used as key and the second element is used as the value. The idea is to traverse all pairs one by one. For every pair, check if its second element is in the hash table. If yes, then compare the first element with the value of the matched entry of the hash table. If the value and the first element match, then we found symmetric pairs. Else, insert the first element as a key and second element as value.
Following is the implementation of this idea.
C++
#include<bits/stdc++.h>using namespace std;// A C++ program to find all symmetric pairs in a given array of pairs// Print all pairs that have a symmetric counterpartvoid findSymPairs(int arr[][2], int row){ // Creates an empty hashMap hM unordered_map<int, int> hM; // Traverse through the given array for (int i = 0; i < row; i++) { // First and second elements of current pair int first = arr[i][0]; int sec = arr[i][1]; // If found and value in hash matches with first // element of this pair, we found symmetry if (hM.find(sec) != hM.end() && hM[sec] == first) cout << "(" << sec << ", " << first << ")" <<endl; else // Else put sec element of this pair in hash hM[first] = sec; }}// Driver methodint main(){ int arr[5][2]; arr[0][0] = 11; arr[0][1] = 20; arr[1][0] = 30; arr[1][1] = 40; arr[2][0] = 5; arr[2][1] = 10; arr[3][0] = 40; arr[3][1] = 30; arr[4][0] = 10; arr[4][1] = 5; findSymPairs(arr, 5);}//This is contributed by Chhavi |
Java
// A Java program to find all symmetric pairs in a given array of pairsimport java.util.HashMap; class SymmetricPairs { // Print all pairs that have a symmetric counterpart static void findSymPairs(int arr[][]) { // Creates an empty hashMap hM HashMap<Integer, Integer> hM = new HashMap<Integer, Integer>(); // Traverse through the given array for (int i = 0; i < arr.length; i++) { // First and second elements of current pair int first = arr[i][0]; int sec = arr[i][1]; // Look for second element of this pair in hash Integer val = hM.get(sec); // If found and value in hash matches with first // element of this pair, we found symmetry if (val != null && val == first) System.out.println("(" + sec + ", " + first + ")"); else // Else put sec element of this pair in hash hM.put(first, sec); } } // Driver method public static void main(String arg[]) { int arr[][] = new int[5][2]; arr[0][0] = 11; arr[0][1] = 20; arr[1][0] = 30; arr[1][1] = 40; arr[2][0] = 5; arr[2][1] = 10; arr[3][0] = 40; arr[3][1] = 30; arr[4][0] = 10; arr[4][1] = 5; findSymPairs(arr); }} |
Python3
# A Python3 program to find all symmetric# pairs in a given array of pairs.# Print all pairs that have# a symmetric counterpartdef findSymPairs(arr, row): # Creates an empty hashMap hM hM = dict() # Traverse through the given array for i in range(row): # First and second elements # of current pair first = arr[i][0] sec = arr[i][1] # If found and value in hash matches with first # element of this pair, we found symmetry if (sec in hM.keys() and hM[sec] == first): print("(", sec,",", first, ")") else: # Else put sec element of # this pair in hash hM[first] = sec# Driver Codeif __name__ == '__main__': arr = [[0 for i in range(2)] for i in range(5)] arr[0][0], arr[0][1] = 11, 20 arr[1][0], arr[1][1] = 30, 40 arr[2][0], arr[2][1] = 5, 10 arr[3][0], arr[3][1] = 40, 30 arr[4][0], arr[4][1] = 10, 5 findSymPairs(arr, 5)# This code is contributed by Mohit Kumar |
C#
// C# program to find all symmetric// pairs in a given array of pairsusing System;using System.Collections.Generic;public class SymmetricPairs{ // Print all pairs that have a symmetric counterpart static void findSymPairs(int [,]arr) { // Creates an empty hashMap hM Dictionary<int,int> hM = new Dictionary<int,int>(); int val = 0; // Traverse through the given array for (int i = 0; i < arr.GetLength(0); i++) { // First and second elements of current pair int first = arr[i, 0]; int sec = arr[i, 1]; // Look for second element of this pair in hash if(hM.ContainsKey(sec)) val = hM[sec]; // If found and value in hash matches with first // element of this pair, we found symmetry if (val != 0 && val == first) Console.WriteLine("(" + sec + ", " + first + ")"); else // Else put sec element of this pair in hash hM.Add(first, sec); } } // Driver code public static void Main(String []arg) { int [,]arr = new int[5, 2]; arr[0, 0] = 11; arr[0, 1] = 20; arr[1, 0] = 30; arr[1, 1] = 40; arr[2, 0] = 5; arr[2, 1] = 10; arr[3, 0] = 40; arr[3, 1] = 30; arr[4, 0] = 10; arr[4, 1] = 5; findSymPairs(arr); }}// This code has been contributed by 29AjayKumar |
Javascript
<script>// A Javascript program to find all symmetric pairs in a given array of pairs // Print all pairs that have a symmetric counterpart function findSymPairs(arr) { // Creates an empty hashMap hM let hM = new Map(); // Traverse through the given array for (let i = 0; i < arr.length; i++) { // First and second elements of current pair let first = arr[i][0]; let sec = arr[i][1]; // Look for second element of this pair in hash let val = hM.get(sec); // If found and value in hash matches with first // element of this pair, we found symmetry if (val != null && val == first) document.write("(" + sec + ", " + first + ")<br>"); else // Else put sec element of this pair in hash hM.set(first, sec); } } // Driver method let arr = new Array(5); for(let i = 0; i < arr.length; i++) { arr[i] = new Array(2); for(let j = 0; j < 2; j++) { arr[i][j] = 0; } } arr[0][0] = 11; arr[0][1] = 20; arr[1][0] = 30; arr[1][1] = 40; arr[2][0] = 5; arr[2][1] = 10; arr[3][0] = 40; arr[3][1] = 30; arr[4][0] = 10; arr[4][1] = 5; findSymPairs(arr); // This code is contributed by unknown2108</script> |
Output:
Following pairs have symmetric pairs (30, 40) (5, 10)
Time Complexity of this solution is O(n) under the assumption that hash search and insert methods work in O(1) time.
This article is contributed by Shivam Agrawal. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
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