Generate two output strings depending upon occurrence of character in input string.

Given an input string str[], generate two output strings. One of which consists of those character which occurs only once in input string and second which consists of multi-time occurring characters. Output strings must be sorted.

Examples:

Input : str[] = "geeksforgeeks"
Output : String with characters occurring once:
for
String with characters occurring multiple times:
egks

Input : str[] = "geekspractice"
Output : String with characters occurring once:
agikprst
String with characters occurring multiple times:
ce

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach : We follow total two steps to generate the both output strings.
Step 1: Create a count array and count occurrences of characters in the given input string.
Step 2: Check count array for each position ‘i’ which leads to three possible conditions :
a) If count value is 1, append character in first output string.
b) If count value is greater than 1, append character in second output string.
c) If count value is 0 do nothing.

Time Complexity for above approach is O(n).
Auxiliary Space required is O(1).

C++

// CPP program to print two strings 
// made of character occurring once  
// and multiple times 
#include <bits/stdc++.h> 
using namespace std; 
  
const int MAX_CHAR = 256; 
  
// function to print two strings  
// generated from single string one 
// with characters occurring onces  
// other with character occurring  
// multiple of times 
void printDuo(string &str) 
{ 
    // initialize hashtable with zero  
    // entry 
    int countChar[MAX_CHAR] = { 0 }; 
  
    // perform hashing for input string 
    int n = str.length(); 
    for (int i = 0; i < n; i++) 
        countChar[str[i] - 'a']++; 
  
    // generate string (str1) consisting  
    // char occurring once and string  
    // (str2) consisting char occurring  
    // multiple times 
    string str1 = "", str2 = "";   
    for (int i = 0; i < MAX_CHAR; i++) { 
        if (countChar[i] > 1) 
            str2 = str2 + (char)(i + 'a'); 
        else if (countChar[i] == 1) 
            str1 = str1 + (char)(i + 'a'); 
    } 
  
    // print both strings 
    cout << "String with characters occurring "
         <<  "once:\n"; 
    cout << str1 << "\n"; 
    cout << "String with characters occurring " 
         << "multiple times:\n"; 
    cout << str2 << "\n"; 
} 
  
// driver program 
int main() 
{ 
    string str = "lovetocode"; 
    printDuo(str); 
    return 0; 
} 

Java

// Java program to print two strings  
// made of character occurring once  
// and multiple times  
  
class GFG { 
  
    final static int MAX_CHAR = 256; 
  
// function to print two strings  
// generated from single string one  
// with characters occurring onces  
// other with character occurring  
// multiple of times  
    static void printDuo(String str) { 
        // initialize hashtable with zero  
        // entry  
        int countChar[] = new int[MAX_CHAR]; 
  
        // perform hashing for input string  
        int n = str.length(); 
        for (int i = 0; i < n; i++) { 
            countChar[str.charAt(i) - 'a']++; 
        } 
  
        // generate string (str1) consisting  
        // char occurring once and string  
        // (str2) consisting char occurring  
        // multiple times  
        String str1 = "", str2 = ""; 
        for (int i = 0; i < MAX_CHAR; i++) { 
            if (countChar[i] > 1) { 
                str2 = str2 + (char) (i + 'a'); 
            } else if (countChar[i] == 1) { 
                str1 = str1 + (char) (i + 'a'); 
            } 
        } 
  
        // print both strings  
        System.out.print("String with characters occurring "
                + "once:\n"); 
        System.out.print(str1 + "\n"); 
        System.out.print("String with characters occurring "
                + "multiple times:\n"); 
        System.out.print(str2 + "\n"); 
        System.out.print(""); 
    } 
  
// driver program  
    public static void main(String[] args) { 
        String str = "lovetocode"; 
        printDuo(str); 
  
    } 
} 
//this code contributed by 29AJayKumar 

Python3

# Python3 program to print two strings
# made of character occurring once
# and multiple times

MAX_CHAR = 256

# function to print two strings
# generated from single string one
# with characters occurring onces
# other with character occurring
# multiple of times
def printDuo(string):

# initialize hashtable with zero
# entry
countChar = [0 for i in range(MAX_CHAR)]

# perform hashing for input string
n = len(string)
for i in range(n):
countChar[ord(string[i]) – ord(‘a’)] += 1

# generate string (str1) consisting
# char occurring once and string
# (str2) consisting char occurring
# multiple times
str1 = “”
str2 = “”
for i in range(MAX_CHAR):
if (countChar[i] > 1):
str2 = str2 + chr(i + ord(‘a’))
elif (countChar[i] == 1):
str1 = str1 + chr(i + ord(‘a’))

# print both strings
print(“String with characters occurring once:”,
“\n”, str1)
print(“String with characters occurring”,
“multiple times:”, “\n”, str2)

# Driver Code
string = “lovetocode”
printDuo(string)

# This code is contributed by
# Mohit kumar 29

C#

// C# program to print two strings  
// made of character occurring once  
// and multiple times  
using System; 
  
class GFG  
{ 
static int MAX_CHAR = 256; 
  
// function to print two strings  
// generated from single string one  
// with characters occurring onces  
// other with character occurring  
// multiple of times  
static void printDuo(string str) 
{ 
    // initialize hashtable with zero  
    // entry  
    int[] countChar = new int[MAX_CHAR]; 
  
    // perform hashing for input string  
    int n = str.Length; 
    for (int i = 0; i < n; i++) 
    { 
        countChar[str[i] - 'a']++; 
    } 
  
    // generate string (str1) consisting  
    // char occurring once and string  
    // (str2) consisting char occurring  
    // multiple times  
    string str1 = "", str2 = ""; 
    for (int i = 0; i < MAX_CHAR; i++) 
    { 
        if (countChar[i] > 1) 
        { 
            str2 = str2 + (char) (i + 'a'); 
        }  
        else if (countChar[i] == 1) 
        { 
            str1 = str1 + (char) (i + 'a'); 
        } 
    } 
  
    // print both strings  
    Console.Write("String with characters "+  
                       "occurring once:\n"); 
    Console.Write(str1 + "\n"); 
    Console.Write("String with characters occurring " +  
                                  "multiple times:\n"); 
    Console.Write(str2 + "\n"); 
    Console.Write(""); 
} 
  
// Driver Code 
public static void Main()  
{ 
    string str = "lovetocode"; 
    printDuo(str); 
} 
} 
  
// This code is contributed by ita_c 

Output:

String with characters occurring once:
cdltv
String with characters occurring multiple times:
eo

This article is contributed by Shivam Pradhan (anuj_charm). If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

My Personal Notes

Suggest a Topic

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C++

Java

Python3

C#

Recommended Posts: