Generate two output strings depending upon occurrence of character in input string.

Given an input string str[], generate two output strings. One of which consists of those character which occurs only once in input string and second which consists of multi-time occurring characters. Output strings must be sorted.

Examples:

Input : str[] = "geeksforgeeks"
Output : String with characters occurring once:
for
String with characters occurring multiple times:
egks

Input : str[] = "geekspractice"
Output : String with characters occurring once:
agikprst
String with characters occurring multiple times:
ce



Approach : We follow total two steps to generate the both output strings.
Step 1: Create a count array and count occurrences of characters in the given input string.
Step 2: Check count array for each position ‘i’ which leads to three possible conditions :
a) If count value is 1, append character in first output string.
b) If count value is greater than 1, append character in second output string.
c) If count value is 0 do nothing.

Time Complexity for above approach is O(n).
Auxiliary Space required is O(1).

C++

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// CPP program to print two strings
// made of character occurring once 
// and multiple times
#include <bits/stdc++.h>
using namespace std;
  
const int MAX_CHAR = 256;
  
// function to print two strings 
// generated from single string one
// with characters occurring onces 
// other with character occurring 
// multiple of times
void printDuo(string &str)
{
    // initialize hashtable with zero 
    // entry
    int countChar[MAX_CHAR] = { 0 };
  
    // perform hashing for input string
    int n = str.length();
    for (int i = 0; i < n; i++)
        countChar[str[i] - 'a']++;
  
    // generate string (str1) consisting 
    // char occurring once and string 
    // (str2) consisting char occurring 
    // multiple times
    string str1 = "", str2 = "";  
    for (int i = 0; i < MAX_CHAR; i++) {
        if (countChar[i] > 1)
            str2 = str2 + (char)(i + 'a');
        else if (countChar[i] == 1)
            str1 = str1 + (char)(i + 'a');
    }
  
    // print both strings
    cout << "String with characters occurring "
         <<  "once:\n";
    cout << str1 << "\n";
    cout << "String with characters occurring " 
         << "multiple times:\n";
    cout << str2 << "\n";
}
  
// driver program
int main()
{
    string str = "lovetocode";
    printDuo(str);
    return 0;
}

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Java

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// Java program to print two strings 
// made of character occurring once 
// and multiple times 
  
class GFG {
  
    final static int MAX_CHAR = 256;
  
// function to print two strings 
// generated from single string one 
// with characters occurring onces 
// other with character occurring 
// multiple of times 
    static void printDuo(String str) {
        // initialize hashtable with zero 
        // entry 
        int countChar[] = new int[MAX_CHAR];
  
        // perform hashing for input string 
        int n = str.length();
        for (int i = 0; i < n; i++) {
            countChar[str.charAt(i) - 'a']++;
        }
  
        // generate string (str1) consisting 
        // char occurring once and string 
        // (str2) consisting char occurring 
        // multiple times 
        String str1 = "", str2 = "";
        for (int i = 0; i < MAX_CHAR; i++) {
            if (countChar[i] > 1) {
                str2 = str2 + (char) (i + 'a');
            } else if (countChar[i] == 1) {
                str1 = str1 + (char) (i + 'a');
            }
        }
  
        // print both strings 
        System.out.print("String with characters occurring "
                + "once:\n");
        System.out.print(str1 + "\n");
        System.out.print("String with characters occurring "
                + "multiple times:\n");
        System.out.print(str2 + "\n");
        System.out.print("");
    }
  
// driver program 
    public static void main(String[] args) {
        String str = "lovetocode";
        printDuo(str);
  
    }
}
//this code contributed by 29AJayKumar

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Python3

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# Python3 program to print two strings
# made of character occurring once 
# and multiple times
  
MAX_CHAR = 256
  
# function to print two strings 
# generated from single string one
# with characters occurring onces 
# other with character occurring 
# multiple of times
def printDuo(string):
  
    # initialize hashtable with zero 
    # entry
    countChar = [0 for i in range(MAX_CHAR)] 
  
    # perform hashing for input string
    n = len(string)
    for i in range(n):
        countChar[ord(string[i]) - ord('a')] += 1
  
    # generate string (str1) consisting 
    # char occurring once and string 
    # (str2) consisting char occurring 
    # multiple times
    str1 = ""
    str2 = "" 
    for i in range(MAX_CHAR): 
        if (countChar[i] > 1):
            str2 = str2 + chr(i + ord('a'))
        elif (countChar[i] == 1):
            str1 = str1 + chr(i + ord('a'))
      
    # print both strings
    print("String with characters occurring once:"
                                        "\n", str1)
    print("String with characters occurring"
               "multiple times:", "\n", str2)
  
# Driver Code
string = "lovetocode"
printDuo(string)
  
# This code is contributed by
# Mohit kumar 29

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C#

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// C# program to print two strings 
// made of character occurring once 
// and multiple times 
using System;
  
class GFG 
{
static int MAX_CHAR = 256;
  
// function to print two strings 
// generated from single string one 
// with characters occurring onces 
// other with character occurring 
// multiple of times 
static void printDuo(string str)
{
    // initialize hashtable with zero 
    // entry 
    int[] countChar = new int[MAX_CHAR];
  
    // perform hashing for input string 
    int n = str.Length;
    for (int i = 0; i < n; i++)
    {
        countChar[str[i] - 'a']++;
    }
  
    // generate string (str1) consisting 
    // char occurring once and string 
    // (str2) consisting char occurring 
    // multiple times 
    string str1 = "", str2 = "";
    for (int i = 0; i < MAX_CHAR; i++)
    {
        if (countChar[i] > 1)
        {
            str2 = str2 + (char) (i + 'a');
        
        else if (countChar[i] == 1)
        {
            str1 = str1 + (char) (i + 'a');
        }
    }
  
    // print both strings 
    Console.Write("String with characters "
                       "occurring once:\n");
    Console.Write(str1 + "\n");
    Console.Write("String with characters occurring "
                                  "multiple times:\n");
    Console.Write(str2 + "\n");
    Console.Write("");
}
  
// Driver Code
public static void Main() 
{
    string str = "lovetocode";
    printDuo(str);
}
}
  
// This code is contributed by ita_c

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Output:

String with characters occurring once:
cdltv
String with characters occurring multiple times:
eo

This article is contributed by Shivam Pradhan (anuj_charm). If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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