Generate two output strings depending upon occurrence of character in input string.
Given an input string str[], generate two output strings. One of which consists of those character which occurs only once in input string and second which consists of multi-time occurring characters. Output strings must be sorted.
Examples:
Input : str[] = "geeksforgeeks" Output : String with characters occurring once: for String with characters occurring multiple times: egks Input : str[] = "geekspractice" Output : String with characters occurring once: agikprst String with characters occurring multiple times: ce
Approach : We follow total two steps to generate the both output strings.
Step 1: Create a count array and count occurrences of characters in the given input string.
Step 2: Check count array for each position ‘i’ which leads to three possible conditions :
a) If count value is 1, append character in first output string.
b) If count value is greater than 1, append character in second output string.
c) If count value is 0 do nothing.
Time Complexity for above approach is O(n).
Auxiliary Space required is O(1).
C++
// CPP program to print two strings // made of character occurring once // and multiple times #include <bits/stdc++.h> using namespace std; const int MAX_CHAR = 256; // function to print two strings // generated from single string one // with characters occurring once // other with character occurring // multiple of times void printDuo(string &str) { // initialize hashtable with zero // entry int countChar[MAX_CHAR] = { 0 }; // perform hashing for input string int n = str.length(); for ( int i = 0; i < n; i++) countChar[str[i] - 'a' ]++; // generate string (str1) consisting // char occurring once and string // (str2) consisting char occurring // multiple times string str1 = "" , str2 = "" ; for ( int i = 0; i < MAX_CHAR; i++) { if (countChar[i] > 1) str2 = str2 + ( char )(i + 'a' ); else if (countChar[i] == 1) str1 = str1 + ( char )(i + 'a' ); } // print both strings cout << "String with characters occurring " << "once:\n" ; cout << str1 << "\n" ; cout << "String with characters occurring " << "multiple times:\n" ; cout << str2 << "\n" ; } // driver program int main() { string str = "lovetocode" ; printDuo(str); return 0; } |
Java
// Java program to print two strings // made of character occurring once // and multiple times class GFG { final static int MAX_CHAR = 256 ; // function to print two strings // generated from single string one // with characters occurring once // other with character occurring // multiple of times static void printDuo(String str) { // initialize hashtable with zero // entry int countChar[] = new int [MAX_CHAR]; // perform hashing for input string int n = str.length(); for ( int i = 0 ; i < n; i++) { countChar[str.charAt(i) - 'a' ]++; } // generate string (str1) consisting // char occurring once and string // (str2) consisting char occurring // multiple times String str1 = "" , str2 = "" ; for ( int i = 0 ; i < MAX_CHAR; i++) { if (countChar[i] > 1 ) { str2 = str2 + ( char ) (i + 'a' ); } else if (countChar[i] == 1 ) { str1 = str1 + ( char ) (i + 'a' ); } } // print both strings System.out.print( "String with characters occurring " + "once:\n" ); System.out.print(str1 + "\n" ); System.out.print( "String with characters occurring " + "multiple times:\n" ); System.out.print(str2 + "\n" ); System.out.print( "" ); } // driver program public static void main(String[] args) { String str = "lovetocode" ; printDuo(str); } } //this code contributed by 29AJayKumar |
Python3
# Python3 program to print two strings # made of character occurring once # and multiple times MAX_CHAR = 256 # function to print two strings # generated from single string one # with characters occurring once # other with character occurring # multiple of times def printDuo(string): # initialize hashtable with zero # entry countChar = [ 0 for i in range (MAX_CHAR)] # perform hashing for input string n = len (string) for i in range (n): countChar[ ord (string[i]) - ord ( 'a' )] + = 1 # generate string (str1) consisting # char occurring once and string # (str2) consisting char occurring # multiple times str1 = "" str2 = "" for i in range (MAX_CHAR): if (countChar[i] > 1 ): str2 = str2 + chr (i + ord ( 'a' )) elif (countChar[i] = = 1 ): str1 = str1 + chr (i + ord ( 'a' )) # print both strings print ( "String with characters occurring once:" , "\n" , str1) print ( "String with characters occurring" , "multiple times:" , "\n" , str2) # Driver Code string = "lovetocode" printDuo(string) # This code is contributed by # Mohit kumar 29 |
C#
// C# program to print two strings // made of character occurring once // and multiple times using System; class GFG { static int MAX_CHAR = 256; // function to print two strings // generated from single string one // with characters occurring once // other with character occurring // multiple of times static void printDuo( string str) { // initialize hashtable with zero // entry int [] countChar = new int [MAX_CHAR]; // perform hashing for input string int n = str.Length; for ( int i = 0; i < n; i++) { countChar[str[i] - 'a' ]++; } // generate string (str1) consisting // char occurring once and string // (str2) consisting char occurring // multiple times string str1 = "" , str2 = "" ; for ( int i = 0; i < MAX_CHAR; i++) { if (countChar[i] > 1) { str2 = str2 + ( char ) (i + 'a' ); } else if (countChar[i] == 1) { str1 = str1 + ( char ) (i + 'a' ); } } // print both strings Console.Write( "String with characters " + "occurring once:\n" ); Console.Write(str1 + "\n" ); Console.Write( "String with characters occurring " + "multiple times:\n" ); Console.Write(str2 + "\n" ); Console.Write( "" ); } // Driver Code public static void Main() { string str = "lovetocode" ; printDuo(str); } } // This code is contributed by ita_c |
Javascript
<script> // javascript program to print two strings // made of character occurring once // and multiple times var MAX_CHAR = 256; // function to print two strings // generated from single string one // with characters occurring once // other with character occurring // multiple of times function printDuo(str) { // initialize hashtable with zero // entry var countChar = Array(MAX_CHAR).fill(0); // perform hashing for input string var n = str.length; for ( var i = 0; i < n; i++) countChar[str[i].charCodeAt(0) - 'a' .charCodeAt(0)]++; // generate string (str1) consisting // char occurring once and string // (str2) consisting char occurring // multiple times var str1 = "" , str2 = "" ; for ( var i = 0; i < MAX_CHAR; i++) { if (countChar[i] > 1) str2 = str2 + String.fromCharCode(i + 'a' .charCodeAt(0)); else if (countChar[i] == 1) str1 = str1 + String.fromCharCode(i + 'a' .charCodeAt(0)); } // print both strings document.write( "String with characters occurring " + "once:<br>" ); document.write( str1 + "<br>" ); document.write( "String with characters occurring " + "multiple times:<br>" ); document.write( str2 + "<br>" ); } // driver program var str = "lovetocode" ; printDuo(str); </script> |
Output:
String with characters occurring once: cdltv String with characters occurring multiple times: eo
Time complexity : O(n)
Auxiliary Space : O(1)
This article is contributed by Shivam Pradhan (anuj_charm). If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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