Shadowing of static functions in Java

In Java, if name of a derived class static function is same as base class static function then the derived class static function shadows (or conceals) the base class static function. For example, the following Java code prints “A.fun()”

filter_none

edit
close

play_arrow

link
brightness_4
code

// file name: Main.java
class A {
   static void fun() {
      System.out.println("A.fun()");
   }
}
  
class B extends A { 
   static void fun() {   
      System.out.println("B.fun()");
   }
}
  
public class Main {
   public static void main(String args[]) {
      A a = new B();
      a.fun();  // prints A.fun()
   }
}

chevron_right


If we make both A.fun() and B.fun() as non-static then the above program would print “B.fun()”.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.



My Personal Notes arrow_drop_up


Article Tags :
Practice Tags :


2


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.