Shadowing of static functions in Java

In Java, if the name of a derived class static function is the same as a base class static function then the base class static function shadows (or conceals) the derived class static function. For example, the following Java code prints “A.fun()”
Note: Static method is a class property, so if a static method is called from a class name or object having a class container then the method of that class is called not the object’s method.

// file name: Main.java 
  
// Parent class 
class A { 
    static void fun() 
    { 
        System.out.println("A.fun()"); 
    } 
} 
  
// B is inheriting A 
// Base class 
class B extends A { 
    static void fun() 
    { 
        System.out.println("B.fun()"); 
    } 
} 
  
// Driver Method 
public class Main { 
    public static void main(String args[]) 
    { 
        A a = new B(); 
        a.fun(); // prints A.fun(); 
  
        // B a = new B(); 
        // a.fun(); // prints B.fun() 
  
        // the variable type decides the method 
        // being invoked, not the assigned object type 
    } 
} 

Output:

A.fun()

Note: If we make both A.fun() and B.fun() as non-static then the above program would print “B.fun()”. While both methods are static types, the variable type decides the method being invoked, not the assigned object type

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