Shadowing of static functions in Java
In Java, if the name of a derived class static function is the same as a base class static function then the base class static function shadows (or conceals) the derived class static function. For example, the following Java code prints “A.fun()”
Note: Static method is a class property, so if a static method is called from a class name or object having a class container then the method of that class is called not the object’s method.
Java
// file name: Main.java// Parent classclass A { static void fun() { System.out.println("A.fun()"); }}// B is inheriting A// Child classclass B extends A { static void fun() { System.out.println("B.fun()"); }}// Driver Methodpublic class Main { public static void main(String args[]) { A a = new B(); a.fun(); // prints A.fun(); // B a = new B(); // a.fun(); // prints B.fun() // the variable type decides the method // being invoked, not the assigned object type }} |
A.fun()
Note: If we make both A.fun() and B.fun() as non-static then the above program would print “B.fun()”. While both methods are static types, the variable type decides the method being invoked, not the assigned object type
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