# Find the resulting Colour Combination

• Last Updated : 04 May, 2021

Given a String of three Colours(G, B, Y) as input, the task is to print the resultant combined colour formed according to the rule given below:

// Rules for colour combination

Blue(B) * Green(G) = Yellow(Y)
Yellow(Y) * Blue(B) = Green(G)
Green(G) * Yellow(Y) = Blue(B)

Examples:

Input: str = "GBYGB"
Output B

Input: str = "BYB"
Output Y

Approach: This problem can be solved as follows:

1. Get the input string.
2. Compare each alphabet with its adjacent characters.
3. Use the above condition to determine the combination.
4. print the output combination.

Below is the implementation of the above approach:

## C++

 // C++ program to find the// resultant colour combination #include using namespace std; // Function to return Colour Combinationchar Colour_Combination(string s){    char temp = s[0];     for (int i = 1; i < s.length(); i++) {        if (temp != s[i]) {             // Check for B * G = Y            if ((temp == 'B' || temp == 'G')                && (s[i] == 'G' || s[i] == 'B'))                temp = 'Y';             // Check for B * Y = G            else if ((temp == 'B' || temp == 'Y')                     && (s[i] == 'Y' || s[i] == 'B'))                temp = 'G';             // Check for Y * G = B            else                temp = 'B';        }    }    return temp;} // Driver Codeint main(int argc, char** argv){    string s = "GBYGB";     cout << Colour_Combination(s);}

## Java

 // Java program to find the// resultant colour combinationclass GfG{     // Function to return Colour Combination    static char Colour_Combination(String s)    {        char temp = s.charAt(0);             for (int i = 1; i < s.length(); i++)        {            if (temp != s.charAt(i))            {                     // Check for B * G = Y                if ((temp == 'B' || temp == 'G')                            && (s.charAt(i) == 'G'                            || s.charAt(i) == 'B'))                    temp = 'Y';                     // Check for B * Y = G                else if ((temp == 'B' || temp == 'Y')                                && (s.charAt(i) == 'Y'                                || s.charAt(i) == 'B'))                    temp = 'G';                     // Check for Y * G = B                else                    temp = 'B';            }        }        return temp;    }     // Driver code    public static void main(String []args)    {        String s = "GBYGB";        System.out.println(Colour_Combination(s));    }} // This code is contributed by Rituraj Jain

## Python3

 # Python 3 program to find the# resultant colour combination # Function to return Colour Combinationdef Colour_Combination(s):    temp = s[0]     for i in range(1, len(s), 1):        if (temp != s[i]):                         # Check for B * G = Y            if ((temp == 'B' or temp == 'G') and                (s[i] == 'G' or s[i] == 'B')):                temp = 'Y'             # Check for B * Y = G            elif ((temp == 'B' or temp == 'Y') and                  (s[i] == 'Y' or s[i] == 'B')):                temp = 'G'             # Check for Y * G = B            else:                temp = 'B'    return temp # Driver Codeif __name__ == '__main__':    s = "GBYGB"     print(Colour_Combination(s)) # This code is contributed by# Surendra_Gangwar

## C#

 // C# program to find the// resultant colour combination     using System; class GFG{         // Function to return Colour Combination    static char Colour_Combination(string s)    {        char temp = s[0];             for (int i = 1; i < s.Length; i++)        {            if (temp != s[i])            {                     // Check for B * G = Y                if ((temp == 'B' || temp == 'G')                    && (s[i] == 'G' || s[i] == 'B'))                    temp = 'Y';                     // Check for B * Y = G                else if ((temp == 'B' || temp == 'Y')                        && (s[i] == 'Y' || s[i] == 'B'))                    temp = 'G';                     // Check for Y * G = B                else                    temp = 'B';            }        }        return temp;    }         // Driver Code    static void Main()    {        string s = "GBYGB";             Console.WriteLine(Colour_Combination(s));    }} // This code is contributed by Ryuga



## Javascript



Output:

B

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