Find Nth term of the series 1, 1, 2, 6, 24…

Given a number N. The task is to write a program to find the Nth term in the below series:

1, 1, 2, 6, 24…

Examples:

Input: 3
Output: 2
For N = 3
Nth term = (N-1)!
         = 2
Input: 5
Output: 24

Nth term of the series is given by below formula:

Nth term = ( N-1)! 

Below is the required implementation:

C++

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// CPP program to find N-th term of the series:
// 1, 1, 2, 6, 24...
#include <iostream>
using namespace std;
  
// calculate Nth term of series
int nthTerm(int N)
{
    if (N <= 1)
        return 1;
  
    int i, fact = 1;
    for (i = 1; i < N; i++)
        fact = fact * i;
  
    return fact;
}
  
// Driver Function
int main()
{
    int N = 3;
  
    cout << nthTerm(N);
  
    return 0;
}

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Java

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// Java program to find the Nth term
import java.io.*;
  
// calculate Nth term of this series
// 1, 1, 2, 6, 24...
class Nth {
    public int nthTerm(int N)
    {
        // By using above formula
        if (N <= 1)
            return 1;
  
        int i, fact = 1;
        for (i = 1; i < N; i++)
            fact = fact * i;
  
        return fact;
    }
}
// Main class for main method
class GFG {
  
    public static void main(String[] args)
    {
  
        int N = 3;
  
        // create object of Class Nth
        Nth a = new Nth();
  
        // call and print Nth term
        System.out.println(a.nthTerm(N));
    }
}

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Python 3

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# Python 3 program to find 
# N-th term of the series: 
# 1, 1, 2, 6, 24... 
  
# Function to calculate 
# Nth term of series 
def nthTerm(n) :
  
    if n <= 1 :
        return 1
  
    fact = 1
    for i in range(1, N) :
        fact = fact * i
  
    return fact
  
# Driver code
if __name__ == "__main__" :
  
    N = 3
  
    # function calling
    print(nthTerm(N))
  
# This code is contributed 
# by ANKITRAI1

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C#

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// C# program to find the 
// Nth term of the series
// 1, 1, 2, 6, 24...
using System;
  
// calculate Nth term 
class GFG 
{
public int nthTerm(int N)
{
    // By using above formula
    if (N <= 1)
        return 1;
  
    int i, fact = 1;
    for (i = 1; i < N; i++)
        fact = fact * i;
  
    return fact;
}
  
// Driver Code
public static void Main()
{
    int N = 3;
  
    // create object of Class GFG
    GFG a = new GFG();
  
    // call and print Nth term
    Console.Write(a.nthTerm(N));
}
}
  
// This code is contributed 
// by ChitraNayal

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PHP

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<?php
// PHP program to find N-th 
// term of the series:
// 1, 1, 2, 6, 24...
  
// calculate Nth term of series
function nthTerm($N)
{
    if ($N <= 1)
        return 1;
  
    $fact = 1;
    for ($i = 1; $i < $N; $i++)
        $fact = $fact * $i;
  
    return $fact;
}
  
// Driver Code
$N = 3;
  
echo nthTerm($N);
  
// This code is contributed 
// by ChitraNayal
?>

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Output:

2


My Personal Notes arrow_drop_up

Strategy Path planning and Destination matters in success No need to worry about in between temporary failures

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Improved By : AnkitRai01, Ita_c