Find the Largest Cube formed by Deleting minimum Digits from a number

Difficulty Level : Hard
Last Updated : 25 May, 2021

Given a number n, the task is to find the largest perfect cube that can be formed by deleting minimum digits(possibly 0) from the number.
X is called a perfect cube if X = Y³ for some Y.
Examples:

Input : 4125
Output : 125
Explanation
125 = 5³. We can form 125 by deleting digit 4 from 4125

Input : 876
Output :8
Explanation
8 = 2³. We can form 8 by deleting digits 7 and 6 from 876

We can generate cubes of all numbers till from 1 to N^1/3 (We don’t consider 0 as 0 is not considered as a perfect cube). We iterate the cubes from largest to the smallest.
Now if we look at the number n given to us, then we know that this number contains only log(n) + 1 digits, thus we can efficiently approach the problem if we treat this number n as a string hereafter.
While iterating on the perfect cubes, we check if the perfect cube is a subsequence of the number n when its represented as a string.If this is the case then the deletions required for changing the number n to the current perfect cube is:

No of deleted digits = No of digits in number n - 
                       Number of digits in current 
                                      perfect cube

Since we want the largest cube number we traverse the array of preprocessed cubes in reverse order.

C++

/* C++ code to implement maximum perfect cube
   formed after deleting  minimum digits */
#include <bits/stdc++.h>
using namespace std;
 
// Returns vector of Pre Processed perfect cubes
vector<string> preProcess(long long int n)
{
    vector<string> preProcessedCubes;
    for (int i = 1; i * i * i <= n; i++) {
        long long int iThCube = i * i * i;
 
        // convert the cube to string and push into
        // preProcessedCubes vector
        string cubeString = to_string(iThCube);
        preProcessedCubes.push_back(cubeString);
    }
    return preProcessedCubes;
}
 
/* Utility function for findLargestCube().
   Returns the Largest cube number that can be formed */
string findLargestCubeUtil(string num,
                    vector<string> preProcessedCubes)
{
    // reverse the preProcessed cubes so that we
    // have the largest cube in the beginning
    // of the vector
    reverse(preProcessedCubes.begin(), preProcessedCubes.end());
 
    int totalCubes = preProcessedCubes.size();
 
    // iterate over all cubes
    for (int i = 0; i < totalCubes; i++) {
        string currCube = preProcessedCubes[i];
 
        int digitsInCube = currCube.length();
        int index = 0;
        int digitsInNumber = num.length();
        for (int j = 0; j < digitsInNumber; j++) {
 
            // check if the current digit of the cube
            // matches with that of the number num
            if (num[j] == currCube[index])
                index++;
             
            if (digitsInCube == index)                
                return currCube;           
        }
    }
 
    // if control reaches here, the its
    // not possible  to form a perfect cube
    return "Not Possible";
}
 
// wrapper for findLargestCubeUtil()
void findLargestCube(long long int n)
{
    // pre process perfect cubes
    vector<string> preProcessedCubes = preProcess(n);
 
    // convert number n to string
    string num = to_string(n);
 
    string ans = findLargestCubeUtil(num, preProcessedCubes);
 
    cout << "Largest Cube that can be formed from "
         << n << " is " << ans << endl;
}
 
// Driver Code
int main()
{
    long long int n;
    n = 4125;
    findLargestCube(n);
 
    n = 876;
    findLargestCube(n);
 
    return 0;
}

Java

/* Java code to implement maximum perfect cube
formed after deleting minimum digits */
import java.util.*;
class GFG
{
 
    // Returns vector of Pre Processed perfect cubes
    static Vector<String> preProcess(int n)
    {
        Vector<String> preProcessedCubes = new Vector<>();
        for (int i = 1; i * i * i <= n; i++)
        {
            int iThCube = i * i * i;
 
            // convert the cube to String and push into
            // preProcessedCubes vector
            String cubeString = String.valueOf(iThCube);
            preProcessedCubes.add(cubeString);
        }
        return preProcessedCubes;
    }
 
    /* Utility function for findLargestCube().
    Returns the Largest cube number that can be formed */
    static String findLargestCubeUtil(String num,
            Vector<String> preProcessedCubes)
    {
        // reverse the preProcessed cubes so that we
        // have the largest cube in the beginning
        // of the vector
        Collections.reverse(preProcessedCubes);
 
        int totalCubes = preProcessedCubes.size();
 
        // iterate over all cubes
        for (int i = 0; i < totalCubes; i++)
        {
            String currCube = preProcessedCubes.get(i);
 
            int digitsInCube = currCube.length();
            int index = 0;
            int digitsInNumber = num.length();
            for (int j = 0; j < digitsInNumber; j++)
            {
 
                // check if the current digit of the cube
                // matches with that of the number num
                if (num.charAt(j) == currCube.charAt(index))
                {
                    index++;
                }
 
                if (digitsInCube == index)
                {
                    return currCube;
                }
            }
        }
 
        // if control reaches here, the its
        // not possible to form a perfect cube
        return "Not Possible";
    }
 
    // wrapper for findLargestCubeUtil()
    static void findLargestCube(int n)
    {
        // pre process perfect cubes
        Vector<String> preProcessedCubes = preProcess(n);
 
        // convert number n to String
        String num = String.valueOf(n);
 
        String ans = findLargestCubeUtil(num, preProcessedCubes);
 
        System.out.println("Largest Cube that can be formed from "
                + n + " is " + ans);
    }
 
    // Driver Code
    public static void main(String[] args)
    {
        int n;
        n = 4125;
        findLargestCube(n);
 
        n = 876;
        findLargestCube(n);
    }
}
 
// This code has been contributed by 29AjayKumar

Python3

# Python3 code to implement maximum perfect
# cube formed after deleting minimum digits
import math as mt
 
# Returns vector of Pre Processed
# perfect cubes
def preProcess(n):
 
    preProcessedCubes = list()
    for i in range(1, mt.ceil(n**(1. / 3.))):
        iThCube = i**3
         
        # convert the cube to string and
        # push into preProcessedCubes vector
        cubeString = str(iThCube)
        preProcessedCubes.append(cubeString)
         
    return preProcessedCubes
 
# Utility function for findLargestCube().
# Returns the Largest cube number that
# can be formed
def findLargestCubeUtil(num,preProcessedCubes):
     
    # reverse the preProcessed cubes so
    # that we have the largest cube in
    # the beginning of the vector
    preProcessedCubes = preProcessedCubes[::-1]
 
    totalCubes = len(preProcessedCubes)
 
    # iterate over all cubes
    for i in range(totalCubes):
        currCube = preProcessedCubes[i]
 
        digitsInCube = len(currCube)
        index = 0
        digitsInNumber = len(num)
        for j in range(digitsInNumber):
             
            # check if the current digit of the cube
            # matches with that of the number num
            if (num[j] == currCube[index]):
                index += 1
             
            if (digitsInCube == index):            
                return currCube        
     
    # if control reaches here, the its
    # not possible to form a perfect cube
    return "Not Possible"
 
# wrapper for findLargestCubeUtil()
def findLargestCube(n):
 
    # pre process perfect cubes
    preProcessedCubes = preProcess(n)
 
    num = str(n)
 
    ans = findLargestCubeUtil(num, preProcessedCubes)
 
    print("Largest Cube that can be formed from",
                                    n, "is", ans)
 
# Driver Code
n = 4125
findLargestCube(n)
 
n = 876
findLargestCube(n)
     
# This code is contributed
# by mohit kumar 29

C#

/* C# code to implement maximum perfect cube
formed after deleting minimum digits */
using System;
using System.Collections.Generic;
 
class GFG
{
 
    // Returns vector of Pre Processed perfect cubes
    static List<String> preProcess(int n)
    {
        List<String> preProcessedCubes = new List<String>();
        for (int i = 1; i * i * i <= n; i++)
        {
            int iThCube = i * i * i;
 
            // convert the cube to String and push into
            // preProcessedCubes vector
            String cubeString = String.Join("",iThCube);
            preProcessedCubes.Add(cubeString);
        }
        return preProcessedCubes;
    }
 
    /* Utility function for findLargestCube().
    Returns the Largest cube number that can be formed */
    static String findLargestCubeUtil(String num,
            List<String> preProcessedCubes)
    {
        // reverse the preProcessed cubes so that we
        // have the largest cube in the beginning
        // of the vector
        preProcessedCubes.Reverse();
 
        int totalCubes = preProcessedCubes.Count;
 
        // iterate over all cubes
        for (int i = 0; i < totalCubes; i++)
        {
            String currCube = preProcessedCubes[i];
 
            int digitsInCube = currCube.Length;
            int index = 0;
            int digitsInNumber = num.Length;
            for (int j = 0; j < digitsInNumber; j++)
            {
 
                // check if the current digit of the cube
                // matches with that of the number num
                if (num[j] == currCube[index])
                {
                    index++;
                }
 
                if (digitsInCube == index)
                {
                    return currCube;
                }
            }
        }
 
        // if control reaches here, the its
        // not possible to form a perfect cube
        return "Not Possible";
    }
 
    // wrapper for findLargestCubeUtil()
    static void findLargestCube(int n)
    {
        // pre process perfect cubes
        List<String> preProcessedCubes = preProcess(n);
 
        // convert number n to String
        String num = String.Join("",n);
 
        String ans = findLargestCubeUtil(num, preProcessedCubes);
 
        Console.WriteLine("Largest Cube that can be formed from "
                + n + " is " + ans);
    }
 
    // Driver Code
    public static void Main(String[] args)
    {
        int n;
        n = 4125;
        findLargestCube(n);
 
        n = 876;
        findLargestCube(n);
    }
}
 
// This code contributed by Rajput-Ji

PHP

<?php
// PHP code to implement maximum perfect
// cube formed after deleting minimum digits
 
// Returns vector of Pre Processed
// perfect cubes
function preProcess($n)
{
 
    $preProcessedCubes = array();
    for ($i = 1; $i * $i * $i < $n; $i++)
    {
        $iThCube = $i * $i * $i;
         
        // convert the cube to string and
        // push into preProcessedCubes vector
        $cubeString = strval($iThCube);
        array_push($preProcessedCubes,$cubeString);
    }
    return $preProcessedCubes;
}
 
// Utility function for findLargestCube().
// Returns the Largest cube number that
// can be formed
function findLargestCubeUtil($num,$preProcessedCubes)
{
    // reverse the preProcessed cubes so
    // that we have the largest cube in
    // the beginning of the vector
    $preProcessedCubes = array_reverse($preProcessedCubes);
 
    $totalCubes = count($preProcessedCubes);
 
    // iterate over all cubes
    for($i = 0; $i < $totalCubes; $i++)
    {
        $currCube = $preProcessedCubes[$i];
 
        $digitsInCube = strlen($currCube);
        $index = 0;
        $digitsInNumber = strlen($num);
        for ($j = 0; $j < $digitsInNumber; $j++)
        {
             
            // check if the current digit of the cube
            // matches with that of the number num
            if ($num[$j] == $currCube[$index])
                $index += 1;
             
            if ($digitsInCube == $index)            
                return $currCube;    
        }
    }
    // if control reaches here, the its
    // not possible to form a perfect cube
    return "Not Possible";
}
 
// wrapper for findLargestCubeUtil()
function findLargestCube($n)
{
 
    // pre process perfect cubes
    $preProcessedCubes = preProcess($n);
 
    $num = strval($n);
 
    $ans = findLargestCubeUtil($num, $preProcessedCubes);
 
    print("Largest Cube that can be formed from ".$n." is ".$ans."\n");
}
 
// Driver Code
$n = 4125;
findLargestCube($n);
 
$n = 876;
findLargestCube($n)
     
// This code is contributed by mits
?>

Javascript

<script>
/* Javascript code to implement maximum perfect cube
formed after deleting minimum digits */
     
    // Returns vector of Pre Processed perfect cubes
    function preProcess(n)
    {
        let preProcessedCubes =[];
        for (let i = 1; i * i * i <= n; i++)
        {
            let iThCube = i * i * i;
   
            // convert the cube to String and push into
            // preProcessedCubes vector
            let cubeString = (iThCube).toString();
            preProcessedCubes.push(cubeString);
        }
        return preProcessedCubes;
    }
     
    /* Utility function for findLargestCube().
    Returns the Largest cube number that can be formed */
    function findLargestCubeUtil(num,preProcessedCubes)
    {
     
        // reverse the preProcessed cubes so that we
        // have the largest cube in the beginning
        // of the vector
        (preProcessedCubes).reverse();
   
        let totalCubes = preProcessedCubes.length;
   
        // iterate over all cubes
        for (let i = 0; i < totalCubes; i++)
        {
            let currCube = preProcessedCubes[i];
   
            let digitsInCube = currCube.length;
            let index = 0;
            let digitsInNumber = num.length;
            for (let j = 0; j < digitsInNumber; j++)
            {
   
                // check if the current digit of the cube
                // matches with that of the number num
                if (num[j] == currCube[index])
                {
                    index++;
                }
   
                if (digitsInCube == index)
                {
                    return currCube;
                }
            }
        }
   
        // if control reaches here, the its
        // not possible to form a perfect cube
        return "Not Possible";
    }
     
    // wrapper for findLargestCubeUtil()
    function findLargestCube(n)
    {
     
        // pre process perfect cubes
        let preProcessedCubes = preProcess(n);
   
        // convert number n to String
        let num = (n).toString();
   
        let ans = findLargestCubeUtil(num, preProcessedCubes);
   
        document.write("Largest Cube that can be formed from "
                + n + " is " + ans+"<br>");
    }
     
    // Driver Code
    let n;
    n = 4125;
    findLargestCube(n);
 
    n = 876;
    findLargestCube(n);
 
// This code is contributed by unknown2108
</script>

Output:

Largest Cube that can be formed from 4125 is 125
Largest Cube that can be formed from 876 is 8

Time Complexity of the above algorithm is O(N^1/3log(N) log(N) is due to the fact that the number of digits in N are Log(N) + 1.

My Personal Notes

Related Articles

Find the Largest Cube formed by Deleting minimum Digits from a number

C++

Java

Python3

C#

PHP

Javascript