Consider a rectangle ABCD, we’re given the co-ordinates of the mid points of side AD and BC (p and q respectively) along with their length L (AD = BC = L). Now given the parameters, we need to print the co-ordinates of the 4 points A, B, C and D.
Examples:
Input : p = (1, 0)
q = (1, 2)
L = 2
Output : (0, 0), (0, 2), (2, 2), (2, 0)
Explanation:
The printed points form a rectangle which
satisfy the input constraints.
Input : p = (1, 1)
q = (-1, -1)
L = 2*sqrt(2)
Output : (0, 2), (-2, 0), (0, -2), (2, 0)
From the problem statement 3 cases can arise :
- The Rectangle is horizontal i.e., AD and BC are parallel to X-axis
- The Rectangle is vertical i.e., AD and BC are parallel to Y-axis
- The Rectangle is inclined at a certain angle with the axes
The first two cases are trivial and can easily be solved using basic geometry. For the third case we need to apply some mathematical concepts to find the points.
Consider the above diagram for clarity. We have the co-ordinates of p and q. Thus we can find the slope of AD and BC (As pq is perpendicular to AD). Once we have the slope of AD, we can find the equation of straight line passing through AD. Now we can apply distance formula to obtain the displacements along X and Y axes.
If slope of AD = m, then m = (p.x- q.x)/(q.y - p.y) and displacement along X axis, dx = L/(2*sqrt(1+m*m)) Similarly, dy = m*L/(2*sqrt(1+m*m))
Now we can simply find the co-ordinates of 4 corners by simply adding and subtracting the displacements obtained accordingly.
Below is the implementation .
C++
// C++ program to find corner points of // a rectangle using given length and middle // points. #include <bits/stdc++.h> using namespace std; // Structure to represent a co-ordinate point struct Point { float x, y; Point() { x = y = 0; } Point(float a, float b) { x = a, y = b; } }; // This function receives two points and length // of the side of rectangle and prints the 4 // corner points of the rectangle void printCorners(Point p, Point q, float l) { Point a, b, c, d; // horizontal rectangle if (p.x == q.x) { a.x = p.x - (l/2.0); a.y = p.y; d.x = p.x + (l/2.0); d.y = p.y; b.x = q.x - (l/2.0); b.y = q.y; c.x = q.x + (l/2.0); c.y = q.y; } // vertical rectangle else if (p.y == q.y) { a.y = p.y - (l/2.0); a.x = p.x; d.y = p.y + (l/2.0); d.x = p.x; b.y = q.y - (l/2.0); b.x = q.x; c.y = q.y + (l/2.0); c.x = q.x; } // slanted rectangle else { // calculate slope of the side float m = (p.x-q.x)/float(q.y-p.y); // calculate displacements along axes float dx = (l /sqrt(1+(m*m))) *0.5 ; float dy = m*dx; a.x = p.x - dx; a.y = p.y - dy; d.x = p.x + dx; d.y = p.y + dy; b.x = q.x - dx; b.y = q.y - dy; c.x = q.x + dx; c.y = q.y + dy; } cout << a.x << ", " << a.y << " n" << b.x << ", " << b.y << "n"; << c.x << ", " << c.y << " n" << d.x << ", " << d.y << "nn"; } // Driver code int main() { Point p1(1, 0), q1(1, 2); printCorners(p1, q1, 2); Point p(1, 1), q(-1, -1); printCorners(p, q, 2*sqrt(2)); return 0; } |
Java
// Java program to find corner points of // a rectangle using given length and middle // points. class GFG { // Structure to represent a co-ordinate point static class Point { float x, y; Point() { x = y = 0; } Point(float a, float b) { x = a; y = b; } }; // This function receives two points and length // of the side of rectangle and prints the 4 // corner points of the rectangle static void printCorners(Point p, Point q, float l) { Point a = new Point(), b = new Point(), c = new Point(), d = new Point(); // horizontal rectangle if (p.x == q.x) { a.x = (float) (p.x - (l / 2.0)); a.y = p.y; d.x = (float) (p.x + (l / 2.0)); d.y = p.y; b.x = (float) (q.x - (l / 2.0)); b.y = q.y; c.x = (float) (q.x + (l / 2.0)); c.y = q.y; } // vertical rectangle else if (p.y == q.y) { a.y = (float) (p.y - (l / 2.0)); a.x = p.x; d.y = (float) (p.y + (l / 2.0)); d.x = p.x; b.y = (float) (q.y - (l / 2.0)); b.x = q.x; c.y = (float) (q.y + (l / 2.0)); c.x = q.x; } // slanted rectangle else { // calculate slope of the side float m = (p.x - q.x) / (q.y - p.y); // calculate displacements along axes float dx = (float) ((l / Math.sqrt(1 + (m * m))) * 0.5); float dy = m * dx; a.x = p.x - dx; a.y = p.y - dy; d.x = p.x + dx; d.y = p.y + dy; b.x = q.x - dx; b.y = q.y - dy; c.x = q.x + dx; c.y = q.y + dy; } System.out.print((int)a.x + ", " + (int)a.y + " \n" + (int)b.x + ", " + (int)b.y + "\n" + (int)c.x + ", " + (int)c.y + " \n" + (int)d.x + ", " + (int)d.y + "\n"); } // Driver code public static void main(String[] args) { Point p1 = new Point(1, 0), q1 = new Point(1, 2); printCorners(p1, q1, 2); Point p = new Point(1, 1), q = new Point(-1, -1); printCorners(p, q, (float) (2 * Math.sqrt(2))); } } // This code contributed by Rajput-Ji |
C#
// C# program to find corner points of // a rectangle using given length and middle // points. using System; class GFG { // Structure to represent a co-ordinate point public class Point { public float x, y; public Point() { x = y = 0; } public Point(float a, float b) { x = a; y = b; } }; // This function receives two points and length // of the side of rectangle and prints the 4 // corner points of the rectangle static void printCorners(Point p, Point q, float l) { Point a = new Point(), b = new Point(), c = new Point(), d = new Point(); // horizontal rectangle if (p.x == q.x) { a.x = (float) (p.x - (l / 2.0)); a.y = p.y; d.x = (float) (p.x + (l / 2.0)); d.y = p.y; b.x = (float) (q.x - (l / 2.0)); b.y = q.y; c.x = (float) (q.x + (l / 2.0)); c.y = q.y; } // vertical rectangle else if (p.y == q.y) { a.y = (float) (p.y - (l / 2.0)); a.x = p.x; d.y = (float) (p.y + (l / 2.0)); d.x = p.x; b.y = (float) (q.y - (l / 2.0)); b.x = q.x; c.y = (float) (q.y + (l / 2.0)); c.x = q.x; } // slanted rectangle else { // calculate slope of the side float m = (p.x - q.x) / (q.y - p.y); // calculate displacements along axes float dx = (float) ((l / Math.Sqrt(1 + (m * m))) * 0.5); float dy = m * dx; a.x = p.x - dx; a.y = p.y - dy; d.x = p.x + dx; d.y = p.y + dy; b.x = q.x - dx; b.y = q.y - dy; c.x = q.x + dx; c.y = q.y + dy; } Console.Write((int)a.x + ", " + (int)a.y + " \n" + (int)b.x + ", " + (int)b.y + "\n" + (int)c.x + ", " + (int)c.y + " \n" + (int)d.x + ", " + (int)d.y + "\n"); } // Driver code public static void Main(String[] args) { Point p1 = new Point(1, 0), q1 = new Point(1, 2); printCorners(p1, q1, 2); Point p = new Point(1, 1), q = new Point(-1, -1); printCorners(p, q, (float) (2 * Math.Sqrt(2))); } } // This code has been contributed by 29AjayKumar |
Output:
0, 0 0, 2 2, 2 2, 0 0, 2 -2, 0 0, -2 2, 0
Reference:
StackOverflow
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