You are given input as order of graph n (highest number of edges connected to a node), you have to find the number of vertices in a Fibonacci cube graph of order n.
Input : n = 3 Output : 5 Explanation : Fib(n + 2) = Fib(5) = 5 Input : n = 2 Output : 3
A Fibonacci Cube Graph is similar to hypercube graph, but with a fibonacci number of vertices. In fibonacci cube graph only 1 vertex has degree n rest all has degree less than n.
Fibonacci cube graph of order n has F(n + 2) vertices, where F(n) is a n-th fibonacci number,
Fibonacii series : 1, 1, 2, 3, 5, 8, 13, 21, 34……………….
For input n as order of graph, find the corresponding fibonacci number at the position n + 2.
where F(n) = F(n – 1) + F(n – 2)
Approach : Find the (n + 2)-th fibonacci number.
Below is the implementation of above approach :
# Python3 code to find vertices in
# a fibonacci cube graph of order n
# Function to find fibonacci number
if n <= 1: return n return fib(n - 1) + fib(n - 2) # Function for finding number of # vertices in fibonacci cube graph def findVertices(n): # return fibonacci number # for f(n + 2) return fib(n + 2) # Driver Code if __name__ == "__main__": # n is the order of the graph n = 3 print(findVertices(n)) # This code is contributed # by Rituraj Jain [tabby title="C#"]
Note that the above code can be optimized to work in O(Log n) using efficient implementations discussed in Program for Fibonacci numbers
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