Skip to content
Related Articles
Get the best out of our app
GeeksforGeeks App
Open App
geeksforgeeks
Browser
Continue

Related Articles

Even and Odd Permutations and their theorems

Improve Article
Save Article
Like Article
Improve Article
Save Article
Like Article

Even Permutations:

A permutation is called even if it can be expressed as a product of even number of transpositions.

Example-1:     
 \begin{pmatrix} 1 & 2 & 3\\ \end{pmatrix}

=\begin{pmatrix} 1 & 2\\ \end{pmatrix} o \begin{pmatrix} 1 & 3\\ \end{pmatrix} = \begin{pmatrix} 1 & 3\\ \end{pmatrix} o \begin{pmatrix} 2 & 3\\ \end{pmatrix}

=\begin{pmatrix} 1 & 3\\ \end{pmatrix} o \begin{pmatrix} 1 & 2\\ \end{pmatrix} o \begin{pmatrix} 1 & 3\\ \end{pmatrix}o \begin{pmatrix} 1 & 2\\ \end{pmatrix}

Here we can see that the permutation ( 1  2  3 ) has been expressed as a product of transpositions in three ways and in each of them the number of transpositions is even, so it is an even permutation.

Example-2: 

 \begin{pmatrix} 1 & 2 & 3&4\\ 2 & 4 & 3&1 \end{pmatrix}

=\begin{pmatrix} 1 & 2 & 3&4\\ 2 & 4 & 3&1 \end{pmatrix} =\begin{pmatrix} 1 & 2 & 4\\ \end{pmatrix}o \begin{pmatrix} 3\\ \end{pmatrix}

=\begin{pmatrix} 1 & 2 & 4\\ \end{pmatrix}= \begin{pmatrix} 1&2\\ \end{pmatrix}o \begin{pmatrix} 1&4\\ \end{pmatrix}

The given permutation is the product of two transpositions so it is an even permutation.

Odd Permutations:

A permutation is called odd if it can be expressed as a product of odd number of transpositions.

Example-1:

\begin{pmatrix} 3 &  4& 5&6\\ \end{pmatrix}

=\begin{pmatrix} 3 &  4& 5&6\\ \end{pmatrix}= \begin{pmatrix} 3 &  4\\ \end{pmatrix}o \begin{pmatrix} 3 &  5\\ \end{pmatrix} o \begin{pmatrix} 3 &  6\\ \end{pmatrix}

= \begin{pmatrix} 3 &  4\\ \end{pmatrix}o \begin{pmatrix} 4 &  5\\ \end{pmatrix}o \begin{pmatrix} 5 &  6\\ \end{pmatrix}o \begin{pmatrix} 6 &  4\\ \end{pmatrix}o \begin{pmatrix} 3 &  5\\ \end{pmatrix}

Here we can see that the permutation ( 3  4  5  6 ) has been expressed as a product of transpositions in two ways and in each of them number of transpositions is odd, so it is an odd permutation.

Example-2:

 \begin{pmatrix} 1&2\\ \end{pmatrix}o \begin{pmatrix} 5&4&3\\ \end{pmatrix}o \begin{pmatrix} 6&7&8\\ \end{pmatrix}

=\begin{pmatrix} 1&2\\ \end{pmatrix}o \begin{pmatrix} 5&4\\ \end{pmatrix}o \begin{pmatrix} 5&3\\ \end{pmatrix} o\begin{pmatrix} 6&7\\ \end{pmatrix}o \begin{pmatrix} 6&8\\ \end{pmatrix}

The given permutation is the product of five transposes so it is an odd permutation.

Theorems on Even and Odd Permutations :

Theorem-1:

If P1 and P2 are permutations, then 

  • (a) P1 P2 is even provided P1 and P2 are either both even or both odd.
  • (b) P1 P2 is odd provided one of P1 and P2 is odd and the other even.

Proof: (a) 

Case I. If P1, P2 both are even. 

Let P1 and P2 be the product of 2n and 2m transpositions respectively, where n and m are positive integers. 

Then each of P1 P2 and P2 P1 is product of 2n + 2m transpositions, where 2n + 2m is evidently an even integer. 

Hence, P1 P2 and P2 P1 are even permutations. 

Case II. If P1, P2 , both are odd. Let P1 P2 be the product of (2n + 1) and (2m + 1) transpositions respectively, where n and m are positive integers. 

Then each of P1 P2 and P2 P1 is the product (2n + 1) + (2m + 1) i.e., 2 (n + m + 1) transpositions, where 2(n + m + 1) is evidently an even integer. 

Hence, P1 P2 and P2 P1 are even permutations. 

Proof : (b) 

Let P1 be an odd and P2 be an even permutation. Also let P1 and P2 be the product of (2n + 1) and 2m transpositions respectively, where n and m are positive integers. 

Then each of P1 P2 and P2 P1 is the product of (2n + 1) + 2m i.e. [ 2 ( n+ m )+1] transpositions , where 2(n+ m) + 1 is evidently an odd integer.

Hence P1 P2 and P2 P1 are odd permutations. 

Theorem-2:
The Identity permutation is an even permutation. 

Proof-: The identity permutation l can always be expressed as the product of two (i.e., even) transpositions. 

For example 

Hence I is an even permutation. (See definition) 

Theorem-3:
The inverse of an even permutation is an even permutation.  

Proof-: If P be an even permutation and P-1 be its inverse, then PP-1= I, the identity permutation.

But P and I are even               (See Theorem 2 above), 

so P-1 is also even                  (See Theorem  1 (a) above)

Theorem-4:
The inverse of an odd permutation is an odd permutation. 

Proof-: If P be an odd permutation and P-1 be its inverse, then PP-1= I, the identity permutation.

But P is odd and I is even.            (See Theorem 2 above),

so P-1 is also odd.                  (See Theorem  1 (b) above)


My Personal Notes arrow_drop_up
Last Updated : 12 Jul, 2022
Like Article
Save Article
Similar Reads