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Mathematics | Problems On Permutations | Set 2
  • Last Updated : 28 Dec, 2020

Prerequisite – Permutation and Combination, Permutations | Set 1

Formula’s Used :

P(n, r) = n! / (n-r)!

Example-1 :
How many words can be formed from the letters of the word WONDER, such that these begin with W and end with R?

Explanation :
If we fix W in the beginning and R at the end,
then the remaining 4 letters can be arranged in 4P4 ways.

Thus, the total number of words which begin with W and end with R



= 4P4 = 4! = 24



Example-2 :
How many numbers are there between 1000 and 10000 in which all the digits are distinct?

Explanation :
We need to form all possible 4-digit numbers with distinct digits as a number between 1000 and 10000 has 4 digits.
At the thousand’s place, we cannot have 0. So, thousand’s place can be filled with 9 ways.
Now, hundred’s place can be filled with any of the remaining 9 digits in 9 ways.
Similarly, tens and units place can be filled in 8 ways and 7 ways respectively as repetition is not allowed.

Thus, total number of required numbers

= 9 * 9 * 8 * 7 = 4536



Example-3 :
How many numbers divisible by 4 and lying between 400 and 500 can be formed from the digits 1, 2, 3, 4, 5, 6, and 7?

Explanation :
A number between 400 and 500 must have 4 at the hundred’s place.
Also, the number is divisible by 4 so it must have 4 at the unit’s place.
Now the tens place can be filled in 7 ways.

Thus, the total number of required numbers

= 1 * 7 * 1 = 7



Example-4 :
How many numbers are there between 1000 and 10000 such that every number is either of 1, 2, or 3?

Explanation :
Every number between 1000 and 10000 is a 4-digit number.
We need to determine the total number of 4 digit numbers such that every digit is either 1, 2, or 3.
For this, each one of thousand’s, hundred’s, ten’s and unit’s place can be filled in 3 ways.

Thus, the total number of required numbers

= 3 * 3 * 3 * 3 = 81



Example-5 :
Tomorrow is Rahul’s birthday and he wants to invite 5 of his friends. He has 4 servants to carry the invitation cards. In how many ways can he send invitation cards to his friends?

Explanation :
A card can be sent by any one of four servants.
Total number of ways of sending a card to 1st friend = 4
Similarly, cards can be sent to each of the 5 friends in 4 ways.
Thus, the total ways of sending cards

= 4 * 4 * 4 * 4 * 4 = 46
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