Difference between sum of the squares of first n natural numbers and square of sum

Given an integer n, find the absolute difference between sum of the squares of first n natural numbers and square of sum of first n natural numbers.

Examples : 

Input : n = 3
Output : 22.0
Sum of first three numbers is 3 + 2 + 1 = 6
Square of the sum =  36
Sum of squares of first three is 9 + 4 + 1 = 14
Absolute difference = 36 - 14 = 22

Input : n = 10
Output : 2640.0

Asked in : biwhiz Company

Approach :
1. Find the sum of square of first n natural numbers.
2. Find the sum of first n numbers and square it.
3. Find the absolute difference between both the sums and print it.

Below is the implementation of above approach :

C++

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ program to find the difference
// between sum of the squares of the
// first n natural numbers and square
// of sum of first n natural number
#include <bits/stdc++.h>
using namespace std;
  
int Square_Diff(int n){
  
int l, k, m;
  
    // Sum of the squares of the
    // first n natural numbers is
    l = (n * (n + 1) * (2 * n + 1)) / 6;
      
    // Sum of n naturals numbers
    k = (n * (n + 1)) / 2;
  
    // Square of k
    k = k * k;
      
    // Differences between l and k
    m = abs(l - k);
      
    return m;
  
}
  
// Driver Code
int main()
{
    int n = 10;
    cout << Square_Diff(n);
    return 0;
      
}
  
// This code is contributed by 'Gitanjali' .

chevron_right






                        filter_none









Java














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// Java program to find the difference 


// between sum of the squares of the 


// first n natural numbers and square 


// of sum of first n natural number 


  


public class GfG{ 


  


static int Square_Diff(int n){ 


  


int l, k, m; 


    // Sum of the squares of the 


    // first n natural numbers is 


    l = (n * (n + 1) * (2 * n + 1)) / 6; 


      


    // Sum of n naturals numbers 


    k = (n * (n + 1)) / 2; 


  


    // Square of k 


    k = k * k; 


      


    // Differences between l and k 


    m = Math.abs(l - k); 


      


    return m; 


  


} 


  


// Driver Code 


public static void main(String s[]) 


{ 


    int n = 10; 


    System.out.println(Square_Diff(n));      


      


} 


}  


// This code is contributed by 'Gitanjali'. 



















                        chevron_right







                        filter_none









Python














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















# Python3 program to find the difference 


# between sum of the squares of the 


# first n natural numbers and square 


# of sum of first n natural number 


  


def Square_Diff(n): 


  


    # sum of the squares of the 


    # first n natural numbers is 


    l = (n * (n + 1) * (2 * n + 1)) / 6


      


    # sum of n naturals numbers 


    k = (n * (n + 1)) / 2


  


    # square of k 


    k = k ** 2


      


    # Differences between l and k 


    m = abs(l - k) 


      


    return m 


  


# Driver code 


print(Square_Diff(10)) 



















                        chevron_right







                        filter_none









C#














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// C# program to find the difference 


// between sum of the squares of the 


// first n natural numbers and square 


// of sum of first n natural number 


using System; 


  


public class GfG{ 


  


static int Square_Diff(int n){ 


  


int l, k, m; 


    // Sum of the squares of the 


    // first n natural numbers is 


    l = (n * (n + 1) * (2 * n + 1)) / 6; 


      


    // Sum of n naturals numbers 


    k = (n * (n + 1)) / 2; 


  


    // Square of k 


    k = k * k; 


      


    // Differences between l and k 


    m = Math.Abs(l - k); 


      


    return m; 


  


} 


  


// Driver Code 


public static void Main() 


{ 


    int n = 10; 


       Console.Write(Square_Diff(n));      


      


} 


}  


// This code is contributed by 'vt_m'. 



















                        chevron_right







                        filter_none









PHP














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















<?php 


// PHP program to find the difference 


// between sum of the squares of the 


// first n natural numbers and square 


// of sum of first n natural number 


  


function Square_Diff($n) 


{ 


  


    $l;  


    $k;  


    $m; 


  


    // Sum of the squares of the 


    // first n natural numbers is 


    $l = ($n * ($n + 1) *  


         (2 * $n + 1)) / 6; 


      


    // Sum of n naturals numbers 


    $k = ($n * ($n + 1)) / 2; 


  


    // Square of k 


    $k = $k * $k; 


      


    // Differences between  


    // l and k 


    $m = abs($l - $k); 


      


    return $m; 


  


} 


  


    // Driver Code 


    $n = 10; 


    echo Square_Diff($n); 


  


// This code is contributed by anuj_67 . 


?> 



















                        chevron_right







                        filter_none










Output : 


2640





    

        My Personal Notes
        arrow_drop_up
    

    

        
        

            
            
        

    


Recommended Posts:
shrikanth13
Check out this Author's contributed articles.
If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please Improve this article if you find anything incorrect by clicking on  the "Improve Article" button below.


Improved By :  vt_m