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# Cyclic shifts of integer N by another integer m

• Last Updated : 27 Aug, 2020

Given an integer N represented as a binary representation of X = 16 bits. We are also given a number ‘m’ and a character c which is either L or R. The task is to determine a number M that is generated after cyclically shifting the binary representation of N by m positions either left if c = L or right if c = R.

Examples:

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Input : N = 7881, m = 5, c = L
Output : 55587
Explanation:
N in binary is 0001 1110 1100 1001 and shifting it left by 5 positions, it becomes 1101 1001 0010 0011 which in the decimal system is 55587.

Input : N = 7881, m = 3, c = R
Output : 9177
Explanation:
N in binary is 0001 1110 1100 1001 and shifted 3 positions to right, it becomes 0010 0011 1101 1001 which in the decimal system is 9177.

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

To solve the problem mentioned above we observe that we have to right shift the number by m if the char is R, else we will do a left shift by m if the char is L where left shifts is equivalent to multiplying a number by 2, right shifts is equivalent to dividing a number by 2.

Below is the implementation of the above approach:

 `# Python implementation to make ``# Cyclic shifts of integer N by another integer m`` ` `def` `Count(N, count, turn):``    ``# Convert N into hexadecimal number and``    ``# remove the initial zeros in it``    ``N ``=` `hex``(``int``(N)).split(``'x'``)[``-``1``]``     ` `    ``# Convert hexadecimal term binary``    ``# string of length = 16 with padded 0s``    ``S ``=` `( ``bin``(``int``(N, ``16``))[``2``:] ).zfill(``16``)``     ` `    ` `    ``# rotate the string by a specific count``    ``if``(turn ``=``=` `'R'``):``        ``S ``=` `(S[``16` `-` `int``(count) : ] ``+` `S[``0` `: ``16` `-` `int``(count)])``         ` `    ``else``:``        ``S ``=` `(S[``int``(count) : ] ``+` `S[``0` `: ``int``(count)])``         ` `    ``# Convert the rotated binary string``    ``# in decimal form, here 2 means in binary form.``    ``print``(``int``(S, ``2``))``     ` `# driver code ``N ``=` `7881``count ``=` `5``turn ``=` `'L'`` ` `Count(N, count, turn)`
Output:
```55587
```

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