Cyclic shifts of integer N by another integer m
Given an integer N represented as a binary representation of X = 16 bits. We are also given a number ‘m’ and a character c which is either L or R. The task is to determine a number M that is generated after cyclically shifting the binary representation of N by m positions either left if c = L or right if c = R.
Examples:
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Input : N = 7881, m = 5, c = L
Output : 55587
Explanation:
N in binary is 0001 1110 1100 1001 and shifting it left by 5 positions, it becomes 1101 1001 0010 0011 which in the decimal system is 55587.Input : N = 7881, m = 3, c = R
Output : 9177
Explanation:
N in binary is 0001 1110 1100 1001 and shifted 3 positions to right, it becomes 0010 0011 1101 1001 which in the decimal system is 9177.
Approach:
To solve the problem mentioned above we observe that we have to right shift the number by m if the char is R, else we will do a left shift by m if the char is L where left shifts is equivalent to multiplying a number by 2, right shifts is equivalent to dividing a number by 2.
Below is the implementation of the above approach:
# Python implementation to make # Cyclic shifts of integer N by another integer m def Count(N, count, turn): # Convert N into hexadecimal number and # remove the initial zeros in it N = hex(int(N)).split('x')[-1] # Convert hexadecimal term binary # string of length = 16 with padded 0s S = ( bin(int(N, 16))[2:] ).zfill(16) # rotate the string by a specific count if(turn == 'R'): S = (S[16 - int(count) : ] + S[0 : 16 - int(count)]) else: S = (S[int(count) : ] + S[0 : int(count)]) # Convert the rotated binary string # in decimal form, here 2 means in binary form. print(int(S, 2)) # driver code N = 7881count = 5turn = 'L' Count(N, count, turn) |
55587
