C++ Program to Print matrix in antispiral form

Given a 2D array, the task is to print matrix in anti spiral form:
Examples:

Output: 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1

Input : arr[][4] = {1, 2, 3, 4
                    5, 6, 7, 8
                    9, 10, 11, 12
                    13, 14, 15, 16};
Output : 10 11 7 6 5 9 13 14 15 16 12 8 4 3 2 1

Input :arr[][6] = {1, 2, 3, 4, 5, 6
                  7, 8, 9, 10, 11, 12
                  13, 14, 15, 16, 17, 18};
Output : 11 10 9 8 7 13 14 15 16 17 18 12 6 5 4 3 2 1

The idea is simple, we traverse matrix in spiral form and put all traversed elements in a stack. Finally one by one elements from stack and print them. 

C++

// C++ program to print matrix in anti-spiral form
#include <bits/stdc++.h>
using namespace std;
#define R 4
#define C 5

void antiSpiralTraversal(int m, int n, int a[R][C])
{
    int i, k = 0, l = 0;

    /*  k - starting row index
        m - ending row index
        l - starting column index
        n - ending column index
        i - iterator  */
    stack<int> stk;

    while (k <= m && l <= n)
    {
        /* Print the first row from the remaining rows */
        for (i = l; i <= n; ++i)
            stk.push(a[k][i]);
        k++;

        /* Print the last column from the remaining columns */
        for (i = k; i <= m; ++i)
            stk.push(a[i][n]);
        n--;

        /* Print the last row from the remaining rows */
        if ( k <= m)
        {
            for (i = n; i >= l; --i)
                stk.push(a[m][i]);
            m--;
        }

        /* Print the first column from the remaining columns */
        if (l <= n)
        {
            for (i = m; i >= k; --i)
                stk.push(a[i][l]);
            l++;
        }
    }

    while (!stk.empty())
    {
        cout << stk.top() << " ";
        stk.pop();
    }
}

/* Driver program to test above functions */
int main()
{
    int mat[R][C] =
    {
        {1,  2,  3,  4,  5},
        {6,  7,  8,  9,  10},
        {11, 12, 13, 14, 15},
        {16, 17, 18, 19, 20}
    };

    antiSpiralTraversal(R-1, C-1, mat);

    return 0;
}

Output:

12 13 14 9 8 7 6 11 16 17 18 19 20 15 10 5 4 3 2 1 

Time Complexity: O(m * n) .

Space Complexity: O(m*n) as stack has been created.

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