Given N, count all ‘a’ and ‘b’ that satisfy the condition a^3 + b^3 = N.

**Examples:**

Input : N = 9 Output : 2 1^3 + 2^3 = 9 2^3 + 1^3 = 9 Input : N = 28 Output : 2 1^3 + 3^3 = 28 3^3 + 1^3 = 28

Note:- (a, b) and (b, a) are to be considered as two different pairs.

Asked in : Adobe

Implementation:Travers numbers from 1 to cube root of N. a) Subtract cube of current number from N and check if their difference is a perfect cube or not. i) If perfect cube then increment count. 2- Return count.

Below is the implementation of above approach:

## C++

`// C++ program to count pairs whose sum ` `// cubes is N ` `#include<bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to count the pairs satisfying ` `// a ^ 3 + b ^ 3 = N ` `int` `countPairs(` `int` `N) ` `{ ` ` ` `int` `count = 0; ` ` ` ` ` `// Check for each number 1 to cbrt(N) ` ` ` `for` `(` `int` `i = 1; i <= cbrt(N); i++) ` ` ` `{ ` ` ` `// Store cube of a number ` ` ` `int` `cb = i*i*i; ` ` ` ` ` `// Subtract the cube from given N ` ` ` `int` `diff = N - cb; ` ` ` ` ` `// Check if the difference is also ` ` ` `// a perfect cube ` ` ` `int` `cbrtDiff = cbrt(diff); ` ` ` ` ` `// If yes, then increment count ` ` ` `if` `(cbrtDiff*cbrtDiff*cbrtDiff == diff) ` ` ` `count++; ` ` ` `} ` ` ` ` ` `// Return count ` ` ` `return` `count; ` `} ` ` ` `// Driver program ` `int` `main() ` `{ ` ` ` `// Loop to Count no. of pairs satisfying ` ` ` `// a ^ 3 + b ^ 3 = i for N = 1 to 10 ` ` ` `for` `(` `int` `i = 1; i<= 10; i++) ` ` ` `cout << ` `"For n = "` `<< i << ` `", "` ` ` `<< countPairs(i) <<` `" pair exists\n"` `; ` ` ` ` ` `return` `0; ` `} ` |

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## Java

`// Java program to count pairs whose sum ` `// cubes is N ` ` ` `class` `Test ` `{ ` ` ` `// method to count the pairs satisfying ` ` ` `// a ^ 3 + b ^ 3 = N ` ` ` `static` `int` `countPairs(` `int` `N) ` ` ` `{ ` ` ` `int` `count = ` `0` `; ` ` ` ` ` `// Check for each number 1 to cbrt(N) ` ` ` `for` `(` `int` `i = ` `1` `; i <= Math.cbrt(N); i++) ` ` ` `{ ` ` ` `// Store cube of a number ` ` ` `int` `cb = i*i*i; ` ` ` ` ` `// Subtract the cube from given N ` ` ` `int` `diff = N - cb; ` ` ` ` ` `// Check if the difference is also ` ` ` `// a perfect cube ` ` ` `int` `cbrtDiff = (` `int` `) Math.cbrt(diff); ` ` ` ` ` `// If yes, then increment count ` ` ` `if` `(cbrtDiff*cbrtDiff*cbrtDiff == diff) ` ` ` `count++; ` ` ` `} ` ` ` ` ` `// Return count ` ` ` `return` `count; ` ` ` `} ` ` ` ` ` `// Driver method ` ` ` `public` `static` `void` `main(String args[]) ` ` ` `{ ` ` ` `// Loop to Count no. of pairs satisfying ` ` ` `// a ^ 3 + b ^ 3 = i for N = 1 to 10 ` ` ` `for` `(` `int` `i = ` `1` `; i<= ` `10` `; i++) ` ` ` `System.out.println(` `"For n = "` `+ i + ` `", "` `+ ` ` ` `+ countPairs(i) + ` `" pair exists"` `); ` ` ` `} ` `} ` |

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## Python 3

`# Python 3 program to count pairs ` `# whose sum cubes is N ` `import` `math ` ` ` `# Function to count the pairs ` `# satisfying a ^ 3 + b ^ 3 = N ` `def` `countPairs(N): ` ` ` ` ` `count ` `=` `0` ` ` ` ` `# Check for each number 1 ` ` ` `# to cbrt(N) ` ` ` `for` `i ` `in` `range` `(` `1` `, ` `int` `(math.` `pow` `(N, ` `1` `/` `3` `) ` `+` `1` `)): ` ` ` ` ` `# Store cube of a number ` ` ` `cb ` `=` `i ` `*` `i ` `*` `i ` ` ` ` ` `# Subtract the cube from given N ` ` ` `diff ` `=` `N ` `-` `cb ` ` ` ` ` `# Check if the difference is also ` ` ` `# a perfect cube ` ` ` `cbrtDiff ` `=` `int` `(math.` `pow` `(diff, ` `1` `/` `3` `)) ` ` ` ` ` `# If yes, then increment count ` ` ` `if` `(cbrtDiff ` `*` `cbrtDiff ` `*` `cbrtDiff ` `=` `=` `diff): ` ` ` `count ` `+` `=` `1` ` ` ` ` `# Return count ` ` ` `return` `count ` ` ` ` ` `# Driver program ` ` ` `# Loop to Count no. of pairs satisfying ` `# a ^ 3 + b ^ 3 = i for N = 1 to 10 ` `for` `i ` `in` `range` `(` `1` `, ` `11` `): ` ` ` `print` `(` `'For n = '` `, i, ` `', '` `, countPairs(i), ` ` ` `' pair exists'` `) ` ` ` ` ` `# This code is contributed by Smitha. ` |

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## C#

`// C# program to count pairs whose sum ` `// cubes is N ` ` ` `using` `System; ` `class` `Test ` `{ ` ` ` `// method to count the pairs satisfying ` ` ` `// a ^ 3 + b ^ 3 = N ` ` ` `static` `int` `countPairs(` `int` `N) ` ` ` `{ ` ` ` `int` `count = 0; ` ` ` ` ` `// Check for each number 1 to cbrt(N) ` ` ` `for` `(` `int` `i = 1; i <= Math.Pow(N,(1.0/3.0)); i++) ` ` ` `{ ` ` ` `// Store cube of a number ` ` ` `int` `cb = i*i*i; ` ` ` ` ` `// Subtract the cube from given N ` ` ` `int` `diff = N - cb; ` ` ` ` ` `// Check if the difference is also ` ` ` `// a perfect cube ` ` ` `int` `cbrtDiff = (` `int` `) Math.Pow(diff,(1.0/3.0)); ` ` ` ` ` `// If yes, then increment count ` ` ` `if` `(cbrtDiff*cbrtDiff*cbrtDiff == diff) ` ` ` `count++; ` ` ` `} ` ` ` ` ` `// Return count ` ` ` `return` `count; ` ` ` `} ` ` ` ` ` `// Driver method ` ` ` `public` `static` `void` `Main() ` ` ` `{ ` ` ` `// Loop to Count no. of pairs satisfying ` ` ` `// a ^ 3 + b ^ 3 = i for N = 1 to 10 ` ` ` `for` `(` `int` `i = 1; i<= 10; i++) ` ` ` `Console.Write(` `"For n = "` `+ i + ` `", "` `+ ` ` ` `+ countPairs(i) + ` `" pair exists"` `+` `"\n"` `); ` ` ` `} ` `} ` |

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## PHP

`<?php ` `// PHP program to count pairs ` `// whose sum cubes is N ` ` ` `// Function to count the pairs ` `// satisfying a ^ 3 + b ^ 3 = N ` `function` `countPairs(` `$N` `) ` `{ ` ` ` `$count` `= 0; ` ` ` ` ` `// Check for each number ` ` ` `// 1 to cbrt(N) ` ` ` `for` `(` `$i` `= 1; ` ` ` `$i` `<= (int)pow(` `$N` `, 1 / 3); ` `$i` `++) ` ` ` `{ ` ` ` `// Store cube of a number ` ` ` `$cb` `= ` `$i` `* ` `$i` `* ` `$i` `; ` ` ` ` ` `// Subtract the cube from ` ` ` `// given N ` ` ` `$diff` `= (` `$N` `- ` `$cb` `); ` ` ` ` ` `// Check if the difference is ` ` ` `// also a perfect cube ` ` ` `$cbrtDiff` `= (int)pow(` `$diff` `, 1 / 3); ` ` ` ` ` `// If yes, then increment count ` ` ` `if` `(` `$cbrtDiff` `* ` `$cbrtDiff` `* ` ` ` `$cbrtDiff` `== ` `$diff` `) ` ` ` `$count` `++; ` ` ` `} ` ` ` ` ` `// Return count ` ` ` `return` `$count` `; ` `} ` ` ` `// Driver Code ` ` ` `// Loop to Count no. of pairs ` `// satisfying a ^ 3 + b ^ 3 = i ` `// for N = 1 to 10 ` `for` `(` `$i` `= 1; ` `$i` `<= 10; ` `$i` `++) ` ` ` `echo` `"For n = "` `, ` `$i` `, ` `", "` `, ` ` ` `countPairs(` `$i` `) ,` `" pair exists\n"` `; ` ` ` `// This code is contributed by jit_t ` `?> ` |

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**Output:**

For n= 1, 1 pair exists For n= 2, 1 pair exists For n= 3, 0 pair exists For n= 4, 0 pair exists For n= 5, 0 pair exists For n= 6, 0 pair exists For n= 7, 0 pair exists For n= 8, 1 pair exists For n= 9, 2 pair exists For n= 10, 0 pair exists

Reference: https://www.careercup.com/question?id=5954491572551680

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