Convert nested Python dictionary to object

Let us see how to convert a given nested dictionary into an object 

Method 1 : Using the json module. We can solve this particular problem by importing the json module and use a custom object hook in the json.loads() method. 

python3

# importing the module
import json

# declaringa a class
class obj:

    # constructor
    def __init__(self, dict1):
        self.__dict__.update(dict1)

def dict2obj(dict1):

    # using json.loads method and passing json.dumps
    # method and custom object hook as arguments
    return json.loads(json.dumps(dict1), object_hook=obj)

# initializing the dictionary
dictionary = {'A': 1, 'B': {'C': 2},
              'D': ['E', {'F': 3}],'G':4}

# calling the function dict2obj and
# passing the dictionary as argument
obj1 = dict2obj(dictionary)

# accessing the dictionary as an object
print (obj1.A)
print(obj1.B.C)
print(obj1.D[0])
print(obj1.D[1].F)
print(obj1.G)

Output

1
2
E
3
4

Time complexity: O(n), where n is the total number of elements in the input dictionary.
Auxiliary space: O(n), where n is the total number of elements in the input dictionary

Method 2: Using the isinstance() method

We can solve this particular problem by using the isinstance() method which is used to check whether an object is an instance of a particular class or not. 

Python3

def dict2obj(d):

    # checking whether object d is a
    # instance of class list
    if isinstance(d, list):
           d = [dict2obj(x) for x in d]

    # if d is not a instance of dict then
    # directly object is returned
    if not isinstance(d, dict):
           return d

    # declaring a class
    class C:
        pass

    # constructor of the class passed to obj
    obj = C()

    for k in d:
        obj.__dict__[k] = dict2obj(d[k])

    return obj

# initializing the dictionary
dictionary = {'A': 1, 'B': {'C': 2},
              'D': ['E', {'F': 3}],'G':4}

# calling the function dict2obj and
# passing the dictionary as argument
obj2 = dict2obj(dictionary)

# accessing the dictionary as an object
print(obj2.A)
print(obj2.B.C)
print(obj2.D[0])
print(obj2.D[1].F)
print(obj2.G)

Output

1
2
E
3
4