Given two numbers **A** and **B**, the task is to check that A and B are in silver ratio.

Silver Ratio:Two numbers are said to be in silver ratio if the ratio of the sum of the smaller and twice the larger number to the larger number is the same as the ratio of the larger one to the smaller one. Below is the representation of the silver ratio:

for A > 0, B > 0

**Examples:**

Input:A = 2.414, B = 1Output:YesExplanation:

Input:A = 1, B = 0.414OutputNoExplanation:Ratio of A to B do not form a golden ratio

**Approach:** The idea is to find two ratios and check whether they are equal to the silver ratio(2.414).

// Here A denotes the larger number

Below is the implementation of the above approach:

## C++

`// C++ implementation to check` `// whether two numbers are in` `// silver ratio with each other` `#include<bits/stdc++.h>` `using` `namespace` `std;` `// Function to check that two` `// numbers are in silver ratio` `bool` `checksilverRatio(` `float` `a, ` `float` `b)` `{` ` ` ` ` `// Swapping the numbers such` ` ` `// that A contains the maximum` ` ` `// number between these numbers` ` ` `if` `(a < b)` ` ` `swap(a, b);` ` ` ` ` `// First Ratio` ` ` `float` `ratio1 = ((a / b) * 1000.0) / 1000.0;` ` ` ` ` `// Second Ratio` ` ` `float` `ratio2 = (` `int` `)(((2 * a + b) /` ` ` `a) * 1000);` ` ` `ratio2 = ratio2 / 1000;` ` ` ` ` `// Condition to check that two` ` ` `// numbers are in silver ratio` ` ` `if` `(ratio1 == ratio2 &&` ` ` `(` `int` `)(ratio1 - 2.414) == 0)` ` ` `{` ` ` `cout << ` `"Yes\n"` `;` ` ` `return` `true` `;` ` ` `}` ` ` `else` ` ` `{` ` ` `cout << ` `"No\n"` `;` ` ` `return` `false` `;` ` ` `}` `}` `// Driver Code` `int` `main()` `{` ` ` `float` `a = 2.414;` ` ` `float` `b = 1;` ` ` ` ` `// Function call` ` ` `checksilverRatio(a, b);` `}` `// This code is contributed by ishayadav181` |

## Java

`// Java implementation to check` `// whether two numbers are in` `// silver ratio with each other` `import` `java.util.*;` `import` `java.lang.*;` `class` `GFG{` `// Function to check that two` `// numbers are in silver ratio` `static` `boolean` `checksilverRatio(` `double` `a,` ` ` `double` `b)` `{` ` ` `// Swapping the numbers such` ` ` `// that A contains the maximum` ` ` `// number between these numbers` ` ` `if` `(a < b)` ` ` `{` ` ` `a = a + b;` ` ` `b = a - b;` ` ` `a = a - b;` ` ` `}` ` ` `// First Ratio` ` ` `double` `ratio1 = ((a / b) * ` `1000` `) / ` `1000` `;` ` ` `// Second Ratio` ` ` `double` `ratio2 = (` `int` `)(((` `2` `* a + b) /` ` ` `a) * ` `1000` `);` ` ` `ratio2 = ratio2 / ` `1000` `;` ` ` `// Condition to check that two` ` ` `// numbers are in silver ratio` ` ` `if` `(ratio1 == ratio2 &&` ` ` `(` `int` `)(ratio1 - ` `2.414` `) == ` `0` `)` ` ` `{` ` ` `System.out.println(` `"Yes"` `);` ` ` `return` `true` `;` ` ` `}` ` ` `else` ` ` `{` ` ` `System.out.println(` `"No"` `);` ` ` `return` `false` `;` ` ` `}` `}` `// Driver Code` `public` `static` `void` `main(String[] args)` `{` ` ` `double` `a = ` `2.414` `;` ` ` `double` `b = ` `1` `;` ` ` `// Function call` ` ` `checksilverRatio(a, b);` `}` `}` `// This code is contributed by jana_sayantan` |

## Python3

`# Python3 implementation to check` `# whether two numbers are in` `# silver ratio with each other` `# Function to check that two` `# numbers are in silver ratio` `def` `checksilverRatio(a, b):` ` ` ` ` `# Swapping the numbers such` ` ` `# that A contains the maximum` ` ` `# number between these numbers` ` ` `a, b ` `=` `max` `(a, b), ` `min` `(a, b)` ` ` ` ` `# First Ratio` ` ` `ratio1 ` `=` `round` `(a ` `/` `b, ` `3` `)` ` ` ` ` `# Second Ratio` ` ` `ratio2 ` `=` `round` `((` `2` `*` `a ` `+` `b)` `/` `a, ` `3` `)` ` ` `# Condition to check that two` ` ` `# numbers are in silver ratio` ` ` `if` `ratio1 ` `=` `=` `ratio2 ` `and` `\` ` ` `ratio1 ` `=` `=` `2.414` `:` ` ` `print` `(` `"Yes"` `)` ` ` `return` `True` ` ` `else` `:` ` ` `print` `(` `"No"` `)` ` ` `return` `False` ` ` `# Driver Code` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `a ` `=` `2.414` ` ` `b ` `=` `1` ` ` ` ` `# Function Call` ` ` `checksilverRatio(a, b)` |

## C#

`// C# implementation to check` `// whether two numbers are in` `// silver ratio with each other` `using` `System;` `class` `GFG{` `// Function to check that two` `// numbers are in silver ratio` `static` `bool` `checksilverRatio(` `double` `a,` ` ` `double` `b)` `{` ` ` `// Swapping the numbers such` ` ` `// that A contains the maximum` ` ` `// number between these numbers` ` ` `if` `(a < b)` ` ` `{` ` ` `a = a + b;` ` ` `b = a - b;` ` ` `a = a - b;` ` ` `}` ` ` `// First Ratio` ` ` `double` `ratio1 = ((a / b) * 1000) / 1000;` ` ` `// Second Ratio` ` ` `double` `ratio2 = (` `int` `)(((2 * a + b) /` ` ` `a) * 1000);` ` ` `ratio2 = ratio2 / 1000;` ` ` `// Condition to check that two` ` ` `// numbers are in silver ratio` ` ` `if` `(ratio1 == ratio2 &&` ` ` `(` `int` `)(ratio1 - 2.414) == 0)` ` ` `{` ` ` `Console.WriteLine(` `"Yes"` `);` ` ` `return` `true` `;` ` ` `}` ` ` `else` ` ` `{` ` ` `Console.WriteLine(` `"No"` `);` ` ` `return` `false` `;` ` ` `}` `}` `// Driver Code` `public` `static` `void` `Main()` `{` ` ` `double` `a = 2.414;` ` ` `double` `b = 1;` ` ` `// Function call` ` ` `checksilverRatio(a, b);` `}` `}` `// This code is contributed by sanjoy_62` |

## Javascript

`<script>` `// Javascript Program to check` `// whether two numbers are in` `// silver ratio with each other` `// Function to check that two` `// numbers are in silver ratio` `function` `checksilverRatio(a, b)` `{` ` ` ` ` `// Swapping the numbers such` ` ` `// that A contains the maximum` ` ` `// number between these numbers` ` ` `if` `(a < b)` ` ` `{` ` ` `a = a + b;` ` ` `b = a - b;` ` ` `a = a - b;` ` ` `}` ` ` ` ` `// First Ratio` ` ` `let ratio1 = ((a / b) * 1000) / 1000;` ` ` ` ` `// Second Ratio` ` ` `let ratio2 = Math.floor(((2 * a + b) /` ` ` `a) * 1000);` ` ` `ratio2 = ratio2 / 1000;` ` ` ` ` `// Condition to check that two` ` ` `// numbers are in silver ratio` ` ` `if` `(ratio1 == ratio2 &&` ` ` `(ratio1 - 2.414) == 0)` ` ` `{` ` ` `document.write(` `"Yes"` `);` ` ` `return` `true` `;` ` ` `}` ` ` `else` ` ` `{` ` ` `document.write(` `"No"` `);` ` ` `return` `false` `;` ` ` `}` `}` `// Driver Code` ` ` `let a = 2.414;` ` ` `let b = 1;` ` ` ` ` `// Function call` ` ` `checksilverRatio(a, b);` ` ` ` ` `// This code is contributed by chinmoy1997pal.` `</script>` |

**Output:**

Yes

**References:** https://en.wikipedia.org/wiki/Silver_ratio

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