Check whether the number formed by concatenating two numbers is a perfect square or not
Given two numbers a and b and the task is to check whether the concatenation of a and b is a perfect square or not.
Examples:
Input: a = 1, b = 21
Output: Yes
121 = 11 × 11, is a perfect square.Input: a = 100, b = 100
Output: No
100100 is not a perfect square.
Approach: Initialize the number as strings initially and concatenate them. Convert the string to a number using Integer.valueOf() function. Once the string has been converted to a number, check if the number is a perfect square or not.
Below is the implementation of the above approach.
C++
// C++ program to check if the // concatenation of two numbers // is a perfect square or not #include <bits/stdc++.h> using namespace std; // Function to check if // the concatenation is // a perfect square void checkSquare(string s1, string s2) { // Function to convert // concatenation of // strings to a number int c = stoi(s1 + s2); // square root of number int d = sqrt (c); // check if it is a // perfect square if (d * d == c) { cout << "Yes" ; } else { cout << "No" ; } } // Driver Code int main() { string s1 = "12" ; string s2 = "1" ; checkSquare(s1, s2); return 0; } |
Java
// Java program to check if the // concatenation of two numbers // is a perfect square or not import java.lang.*; class GFG { // Function to check if the concatenation is // a perfect square static void checkSquare(String s1, String s2) { // Function to convert concatenation // of strings to a number int c = Integer.valueOf(s1 + s2); // square root of number int d = ( int )Math.sqrt(c); // check if it is a perfect square if (d * d == c) { System.out.println( "Yes" ); } else { System.out.println( "No" ); } } // Driver Code public static void main(String[] args) { String s1 = "12" ; String s2 = "1" ; checkSquare(s1, s2); } } |
Python 3
# Python 3 program to check if the
# concatenation of two numbers
# is a perfect square or not
import math
# Function to check if the concatenation
# is a perfect square
def checkSquare(s1, s2):
# Function to convert concatenation of
# strings to a number
c = int(s1 + s2)
# square root of number
d = math.sqrt(c)
# check if it is a perfect square
if (d * d == c) :
print(“Yes”)
else:
print(“No”)
# Driver Code
if __name__ == “__main__”:
s1 = “12”
s2 = “1”
checkSquare(s1, s2)
# This code is contributed by ita_c
C#
// C# program to check if the // concatenation of two numbers // is a perfect square or not using System; public class GFG { // Function to check if the concatenation is // a perfect square static void checkSquare(String s1, String s2) { // Function to convert concatenation // of strings to a number int c = Convert.ToInt32(s1 + s2 ); //int.ValueOf(s1 + s2); // square root of number int d = ( int )Math.Sqrt(c); // check if it is a perfect square if (d * d == c) { Console.WriteLine( "Yes" ); } else { Console.WriteLine( "No" ); } } // Driver Code public static void Main() { String s1 = "12" ; String s2 = "1" ; checkSquare(s1, s2); } } // This code is contributed by PrinciRaj1992 |
PHP
<?php // PHP program to check if the // concatenation of two numbers // is a perfect square or not // Function to check if the // concatenation is a perfect square function checkSquare( $s1 , $s2 ) { // Function to convert concatenation // of strings to a number $c = $s1 . $s2 ; // square root of number $d = sqrt( $c ); // check if it is a // perfect square if ( $d * $d == $c ) { echo "Yes" ; } else { echo "No" ; } } // Driver Code $s1 = "12" ; $s2 = "1" ; checkSquare( $s1 , $s2 ); // This code is contributed by Rajput-Ji ?> |
Yes
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