Given a number you have to check whether there is pair of adjacent set bit or not.

**Examples :**

Input : N = 67 Output : Yes There is a pair of adjacent set bit The binary representation is 100011Input : N = 5 Output : No

A **simple solution** is traverse all bits. For every set bit, check if next bit is also set.

An efficient solution is to shift number by 1 and then do bitwise AND. If bitwise AND is non-zero then there are two adjacent set bits. Else not.

## C++

`// CPP program to check ` `// if there are two ` `// adjacent set bits. ` `#include <iostream> ` `using` `namespace` `std; ` ` ` `bool` `adjacentSet(` `int` `n) ` `{ ` ` ` `return` `(n & (n >> 1)); ` `} ` ` ` `// Driver Code ` `int` `main() ` `{ ` ` ` `int` `n = 3; ` ` ` `adjacentSet(n) ? ` ` ` `cout << ` `"Yes"` `: ` ` ` `cout << ` `"No"` `; ` ` ` `return` `0; ` `} ` |

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## Java

`// Java program to check ` `// if there are two ` `// adjacent set bits. ` `class` `GFG ` `{ ` ` ` ` ` `static` `boolean` `adjacentSet(` `int` `n) ` ` ` `{ ` ` ` `int` `x = (n & (n >> ` `1` `)); ` ` ` ` ` `if` `(x > ` `0` `) ` ` ` `return` `true` `; ` ` ` `else` ` ` `return` `false` `; ` ` ` `} ` ` ` ` ` `// Driver code ` ` ` `public` `static` `void` `main(String args[]) ` ` ` `{ ` ` ` ` ` `int` `n = ` `3` `; ` ` ` ` ` `if` `(adjacentSet(n)) ` ` ` `System.out.println(` `"Yes"` `); ` ` ` `else` ` ` `System.out.println(` `"No"` `); ` ` ` ` ` `} ` `} ` ` ` `// This code is contributed by Sam007. ` |

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## Python3

`# Python 3 program to check if there ` `# are two adjacent set bits. ` ` ` `def` `adjacentSet(n): ` ` ` `return` `(n & (n >> ` `1` `)) ` ` ` `# Driver Code ` `if` `__name__ ` `=` `=` `'__main__'` `: ` ` ` `n ` `=` `3` ` ` `if` `(adjacentSet(n)): ` ` ` `print` `(` `"Yes"` `) ` ` ` `else` `: ` ` ` `print` `(` `"No"` `) ` ` ` `# This code is contributed by ` `# Shashank_Sharma ` |

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## C#

`// C# program to check ` `// if there are two ` `// adjacent set bits. ` `using` `System; ` ` ` `class` `GFG ` `{ ` ` ` `static` `bool` `adjacentSet(` `int` `n) ` ` ` `{ ` ` ` `int` `x = (n & (n >> 1)); ` ` ` ` ` `if` `(x > 0) ` ` ` `return` `true` `; ` ` ` `else` ` ` `return` `false` `; ` ` ` `} ` ` ` ` ` `// Driver code ` ` ` `public` `static` `void` `Main () ` ` ` `{ ` ` ` `int` `n = 3; ` ` ` ` ` `if` `(adjacentSet(n)) ` ` ` `Console.WriteLine(` `"Yes"` `); ` ` ` `else` ` ` `Console.WriteLine(` `"No"` `); ` ` ` `} ` ` ` `} ` ` ` `// This code is contributed by Sam007. ` |

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## php

`<?php ` `// PHP program to check ` `// if there are two ` `// adjacent set bits. ` ` ` `function` `adjacentSet(` `$n` `) ` `{ ` ` ` `return` `(` `$n` `& (` `$n` `>> 1)); ` `} ` ` ` `// Driver Code ` `$n` `= 3; ` `adjacentSet(` `$n` `) ? ` ` ` `print` `(` `"Yes"` `) : ` ` ` `print` `(` `"No"` `); ` ` ` `// This code is contributed by Sam007. ` `?> ` |

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**Output :**

Yes

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